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Jayson,
Nice graphical solution to visualizing the "float turnover" issue.
The solutions that you post always have a positive surprise in terms
of the ultra nice graphical representations that you develope.
When your code is coupled with float = GetExtraData("SharesFloat") *
100000, the resulting graphics *really* stimulate the old neurons. (In
fact I am still not sure whether I am seeing mirage *price cycles*, or
the real thing). I'll work thru it later.
But the visual effects of your code are really neat.
Take Care,
Phsst
--- In amibroker@xxxxxxxxxxxxxxx, "Jayson" <jcasavant@xxxx> wrote:
> Dennis,
> understood but....... the sum of the volume will never (almost
never) equal;
> the exact number of the float which is why I suggested the greater than
> float solution. Now we are talking about something very different.
There may
> be a solution found in looping through the bars and accumulating
volume. In
> this code I have (I think) set X to the initial volume then accumulated
> volume each day until such time as the Float value was met. When this
> occurred I reset X to zero and began accumulating again. The green
dots show
> each rollover. The histogram shows where you are in the current
cycle. The
> title indicates the number of bars since the last turn over as well
as how
> many bars the previous turn over took. Lastly I have averaged the last 2
> rolls.
>
> I got carried away but used the exercise to work on my looping
skills (lack
> of, there may still be problems I have missed). That said I think
you will
> find the notion of rollover to be a bit subjective. In theory you
would want
> to see significant moves begin/end at or near the rollover point. In
> practice there are many participants , all with their own agendas,
and few
> actually monitoring these roll over points.
>
> Regards,
> Jayson
>
> float=630000000;
> x[0]=Volume[0]; /*Initialise the first element here*/
> for(i = 1; i<BarCount; i++)
> {
>
> if(x[i]<float)
> { x[i] = x[i-1]+Volume[i];
> }
> if(x[i]>float)
> {
> x[i]=0;
> }
> }
> Plot(C,"",4,64);
> PlotShapes(IIf(x==0,shapeCircle,shapeNone),5,0,Graph0,-30);
> Plot(x,"",colorLightGrey,2|styleOwnScale);
> //Plot(float,"",colorWhite);
> GraphXSpace=25;
> Count1=BarIndex()-ValueWhen(x==0,BarIndex(),1);
> Count2=ValueWhen(x==0,BarIndex(),1)-ValueWhen(x==0,BarIndex(),2);
> Count3=ValueWhen(x==0,BarIndex(),2)-ValueWhen(x==0,BarIndex(),3);
> Title= " Bars Since the last float rollover "+Count1+ " The previous
> Rollover took "+Count2+ "\n The average of the last 2 rollovers was "
> +(Count2+Count3)/2;
> -----Original Message-----
> From: theoldchartreader [mailto:theoldchartreader@x...]
> Sent: Sunday, December 07, 2003 3:05 PM
> To: amibroker@xxxxxxxxxxxxxxx
> Subject: [amibroker] Re: Float and Sum question
>
>
> Hi Jason,
> First let me thank you for your help,
> Let me try to explain what I am trying to do.
> I will use intel for a example, I am using a weekly chart.
> starting from 12/05/03 to 7/07/03 intel did one float turnover.
> It also did one from 2/07/03 to 7/07/03.( it seems to do one complete
> float turnover every 22 to 24 weeks for the last six float turnovers)
> I used a spreadsheet to total the volume.
> I would like to place shapecircle only at the point of each float
> turnover to mark the spot.
>
> Do we need to divided the sum of volume by the float, for a float
> turnover?
>
> Anyway thank once you again,
> Dennis
>
>
>
>
>
>
>
> --- In amibroker@xxxxxxxxxxxxxxx, "Jayson" <jcasavant@xxxx> wrote:
> > Dennis,
> > the chances of the sum of volume to match the float is very slim
> indeed.
> > Perhaps have the sum exceed the float??
> >
> > float=630000000;
> > x=Sum(Volume,220);
> > plot(c,"Price",4,64);
> > PlotShapes(IIf(x>float,shapeCircle,shapeNone),5);
> >
> > Regards,
> > Jayson
> > -----Original Message-----
> > From: theoldchartreader [mailto:theoldchartreader@x...]
> > Sent: Sunday, December 07, 2003 10:26 AM
> > To: amibroker@xxxxxxxxxxxxxxx
> > Subject: [amibroker] Float and Sum question
> >
> >
> > Hi,
> > I would like to plot a shapecircle every time the sum of volume
> > equals the float?
> >
> > What do I need to do?
> >
> >
> > float=630000000;
> > Sum(Volume,220);
> >
> >
> > thank you,
> > Dennis
> >
> >
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