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Roy, when is the big day for the inaugural release of your "MetaStock
Tips & Tricks" newsletter?
Is the "MetaStock Tips & Tricks" site up and running soon?
Regards,
jose
--- In Metastockusers@xxxxxxxxxxxxxxx, "Roy Larsen" <rlarsen@xxxx>
wrote:
> Tom
>
> I'll have to put that in the "too hard" basket I think
>
> Roy
>
> ----- Original Message -----
> From: "Tom Sprunger" <tlsprunger@xxxx>
> To: <Metastockusers@xxxxxxxxxxxxxxx>
> Sent: Tuesday, July 20, 2004 1:06 PM
> Subject: Re: [Metastockusers] formula question
>
>
> > Roy, the java script formula says
> >
> > n is a constant.
> > set i=n,
> > then for each value of i between 20 and 1, start with i=20 and
decrement i
> > by 1 on each pass,
> > summing up the values of the equation
> > (i - (n + 1) / 3) * close(i - n)
> >
> > The way the bars are identififed in this program is by a numbering
scheme
> > like Metastock uses.
> > Hence, the close(0) = close in metastock terms, and close(-1) is
the same
> > as Ref(close,-1), etc.
> >
> > So, this starts out with a value i=20 and does a loop until i=1.
> > the first pass through it evaluates
> > sum=(20-(20+1)/3)*close(20-20))
> > The next pass through it is
> > sum=(19-(20+1)/3)*Ref(close,(19-20)) +prev
> > The next pass through it becomes
> > sum=(18-(20+1)/3)*Ref(close,(18-20)) + prev
> > and so on until it stops when the value of i becomes zero.
> >
> > There is nothing magic about decrementing the value of i.
> > you could also start with i=1 and increment by 1 until you get to
20.
> > In that case the first pass through would be
> > sum=(1-(20+1)/3)*Ref(close(1-20)
> > etc.
> >
> > The part I can't figure out is how to do the increment/decrement
portion of
> > i.
> > That is because the value i changes inversely to the bar number.
When i is
> > small, the bar number is the oldest (most negative)... When i is
max the
> > bar is the current one.
> >
> > Of course one could hard code it with a long series of Ref(Close,-
x)
> > expressions, but then you can not make n a variable
> > Did I make it clear or am I still confusing you?
> >
> >
> > Tom
> >
> > ----- Original Message -----
> > From: "Roy Larsen" <rlarsen@xxxx>
> > To: <Metastockusers@xxxxxxxxxxxxxxx>
> > Sent: Monday, July 19, 2004 6:59 PM
> > Subject: Re: [Metastockusers] formula question
> >
> >
> > > Tom
> > >
> > > What is it doing in English?
> > >
> > > Roy
> > >
> > > ----- Original Message -----
> > > From: "tlsprunger" <tlsprunger@xxxx>
> > > To: <Metastockusers@xxxxxxxxxxxxxxx>
> > > Sent: Tuesday, July 20, 2004 3:57 AM
> > > Subject: [Metastockusers] formula question
> > >
> > >
> > > > I wonder if any wizards can help me with following.
> > > >
> > > > I have a formula written in Java Script similar to the
following:
> > > > n=20;
> > > > for(i = n; i > 0; i--)
> > > > sum += (i - (n + 1) / 3) * close(i - n);
> > > >
> > > > Now how would I convert that to Metastock language?
> > > >
> > > > note that when the current bar is the "0" bar, the value of i
is 20.
> > > > When the current bar is the "-1" bar, the value of i is 19,
etc.
> > > >
> > > > For example if the part "i-" were not in the equation, then I
could
> > > > do the following:
> > > > n=20;
> > > > x1=n+1)/3)*C;
> > > > x=sum(x1,n);
> > > > and it will sum up the values of x1 over the last 20 bars.
> > > >
> > > > Now how do I get it to add the "i-" part?
> > > >
> > > > Perhaps Metastock can not do this?
> > > >
> > > >
> > > >
> > > >
> > > >
> > > >
> > > >
> > > >
> > > > Yahoo! Groups Links
> > > >
> > > >
> > > >
> > > >
> > > >
> > > >
> > > >
> > >
> > >
> > >
> > >
> > >
> > > Yahoo! Groups Links
> > >
> > >
> > >
> > >
> > >
> > >
> >
> >
> >
> >
> >
> > Yahoo! Groups Links
> >
> >
> >
> >
> >
> >
> >
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