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Tom
I'll have to put that in the "too hard" basket I think
Roy
----- Original Message -----
From: "Tom Sprunger" <tlsprunger@xxxxxxxxxxx>
To: <Metastockusers@xxxxxxxxxxxxxxx>
Sent: Tuesday, July 20, 2004 1:06 PM
Subject: Re: [Metastockusers] formula question
> Roy, the java script formula says
>
> n is a constant.
> set i=n,
> then for each value of i between 20 and 1, start with i=20 and decrement i
> by 1 on each pass,
> summing up the values of the equation
> (i - (n + 1) / 3) * close(i - n)
>
> The way the bars are identififed in this program is by a numbering scheme
> like Metastock uses.
> Hence, the close(0) = close in metastock terms, and close(-1) is the same
> as Ref(close,-1), etc.
>
> So, this starts out with a value i=20 and does a loop until i=1.
> the first pass through it evaluates
> sum=(20-(20+1)/3)*close(20-20))
> The next pass through it is
> sum=(19-(20+1)/3)*Ref(close,(19-20)) +prev
> The next pass through it becomes
> sum=(18-(20+1)/3)*Ref(close,(18-20)) + prev
> and so on until it stops when the value of i becomes zero.
>
> There is nothing magic about decrementing the value of i.
> you could also start with i=1 and increment by 1 until you get to 20.
> In that case the first pass through would be
> sum=(1-(20+1)/3)*Ref(close(1-20)
> etc.
>
> The part I can't figure out is how to do the increment/decrement portion of
> i.
> That is because the value i changes inversely to the bar number. When i is
> small, the bar number is the oldest (most negative)... When i is max the
> bar is the current one.
>
> Of course one could hard code it with a long series of Ref(Close,-x)
> expressions, but then you can not make n a variable
> Did I make it clear or am I still confusing you?
>
>
> Tom
>
> ----- Original Message -----
> From: "Roy Larsen" <rlarsen@xxxxxxxxxxxxxx>
> To: <Metastockusers@xxxxxxxxxxxxxxx>
> Sent: Monday, July 19, 2004 6:59 PM
> Subject: Re: [Metastockusers] formula question
>
>
> > Tom
> >
> > What is it doing in English?
> >
> > Roy
> >
> > ----- Original Message -----
> > From: "tlsprunger" <tlsprunger@xxxxxxxxxxx>
> > To: <Metastockusers@xxxxxxxxxxxxxxx>
> > Sent: Tuesday, July 20, 2004 3:57 AM
> > Subject: [Metastockusers] formula question
> >
> >
> > > I wonder if any wizards can help me with following.
> > >
> > > I have a formula written in Java Script similar to the following:
> > > n=20;
> > > for(i = n; i > 0; i--)
> > > sum += (i - (n + 1) / 3) * close(i - n);
> > >
> > > Now how would I convert that to Metastock language?
> > >
> > > note that when the current bar is the "0" bar, the value of i is 20.
> > > When the current bar is the "-1" bar, the value of i is 19, etc.
> > >
> > > For example if the part "i-" were not in the equation, then I could
> > > do the following:
> > > n=20;
> > > x1=n+1)/3)*C;
> > > x=sum(x1,n);
> > > and it will sum up the values of x1 over the last 20 bars.
> > >
> > > Now how do I get it to add the "i-" part?
> > >
> > > Perhaps Metastock can not do this?
> > >
> > >
> > >
> > >
> > >
> > >
> > >
> > >
> > > Yahoo! Groups Links
> > >
> > >
> > >
> > >
> > >
> > >
> > >
> >
> >
> >
> >
> >
> > Yahoo! Groups Links
> >
> >
> >
> >
> >
> >
>
>
>
>
>
> Yahoo! Groups Links
>
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