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Roy,
I don't know if you had seen this, but while I was working on something
else, I needed some way to have a counter from within a Sum( ) function.
Like:
Sum(counter*2,4);
Which would result in:
(1 x 2) + (2x2) + (3x2) + (4x2) = 20
I came up with:
LastValue(Cum(1)+PREV-PREV)-Ref(Cum(1),-1)
as used inside a Sum function like:
X:=Sum( (LastValue(Cum(1)+PREV-PREV)-Ref(Cum(1),-1) )*2,4);
X {=20}
I realize this is really ugly, and would appreciate it if you know of a
better incremental counter that could be used within a Sum( ) function.
Thanks,
-Corey Saxe
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