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What does the Chandelier Exit tell you? Is this part of an exit strategy? Is there more to this
formula that what you have written there?
Thanks,
> ** Original Subject: RE: Fast Chandelier Exit
> ** Original Sender: "A.J. Maas" <anthmaas@xxxxxxxxx>
> ** Original Date: Sun, 16 Apr 2000 18:09:02 -0500 (CDT)
> ** Original Message follows...
>
> vPrev:=PREV;
> Ndays:=If(Cum(1) < 50,Cum(1),vPrev);
> Ndays2:=If(Ndays>0,Ndays,LastValue(Ndays>0));
> Ndays2
>
> Regards,
> Ton Maas
> ms-irb@xxxxxxxxxxxxxxxx
> Dismiss the ".nospam" bit (including the dot) when replying.
> Homepage http://home.planet.nl/~anthmaas
>
>
> ----- Original Message -----
> From: Dr. R.BHANJA
> To: metastock@xxxxxxxxxxxxx
> Sent: zondag 16 april 2000 19:25
> Subject: Fast Chandelier Exit
>
>
> On February,18,2000 there are some messages regarding using of vPREV
> function for Fast Chandelier Exit. I was trying to test it in some of
> programs. But I could not. Can any body give the solution. I took the
> example in this way
> vPrev:=PREV;
> Ndays:=If(Cum(1) < 50,Cum(1),vPrev);
> Ndays
> While displaying Ndays it gives 0 after 49 but I am interested to get
> Ndays as 49 continuously after 49th day. But if I use
> Ndays:=If(Cum(1) < 50,Cum(1),PREV);
> Ndays
> Then I get correct answer. Can any body give an example of how to use this
> pwerful vPREV function?
> BHANJA
>** --------- End Original Message ----------- **
>
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