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RE: Fast Chandelier Exit



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What does the Chandelier Exit tell you?  Is this part of an exit strategy?  Is there more to this 
formula that what you have written there?

Thanks,


> ** Original Subject: RE: Fast Chandelier Exit
> ** Original Sender: "A.J. Maas" <anthmaas@xxxxxxxxx>
> ** Original Date: Sun, 16 Apr 2000 18:09:02 -0500 (CDT)

> ** Original Message follows... 

>
> vPrev:=PREV;
> Ndays:=If(Cum(1) < 50,Cum(1),vPrev);
> Ndays2:=If(Ndays>0,Ndays,LastValue(Ndays>0));
> Ndays2
> 
> Regards,
> Ton Maas
> ms-irb@xxxxxxxxxxxxxxxx
> Dismiss the ".nospam" bit (including the dot) when replying.
> Homepage  http://home.planet.nl/~anthmaas
> 
> 
>   ----- Original Message -----
>   From: Dr. R.BHANJA
>   To: metastock@xxxxxxxxxxxxx
>   Sent: zondag 16 april 2000 19:25
>   Subject: Fast Chandelier Exit
> 
> 
>   On February,18,2000 there are some messages regarding using of vPREV
> function for Fast Chandelier Exit. I was trying to test it in some of
> programs. But I could not. Can any body give the solution. I took the
> example in this way
>   vPrev:=PREV;
>   Ndays:=If(Cum(1) < 50,Cum(1),vPrev);
>   Ndays
>   While displaying Ndays it gives 0 after 49 but  I am interested to get
> Ndays as 49 continuously after 49th day. But if I use
>   Ndays:=If(Cum(1) < 50,Cum(1),PREV);
>   Ndays
>   Then I get correct answer. Can any body give an example of how to use this
> pwerful vPREV function?
>   BHANJA


>** --------- End Original Message ----------- **

>