I haven't tested, but I don't think that that will work. Given a
history of:
7,7,8,7,10 and current value of 9
Ref(HHV(C, 5),
-1) will give 10, correct?
The current value of 9 is not greater than
10 so we get false (or 0).
But, 9 *is* greater than each of 7,7,8,7 so we
actually wanted a true
(or 1) here since the current value of 9 is greater
than at least 4 of
the preceding 5 values.
Mike
--- In amibroker@xxxxxxxxxps.com,
"Paul Ho" <paul.tsho@x..> wrote:
>
> c >
ref(hhv(c,5), -1)
>
>
> _____
>
> From:
amibroker@xxxxxxxxxps.com
[mailto:amibroker@xxxxxxxxxps.com]
On Behalf
> Of Mike
> Sent: Friday, 12 September 2008 11:26
AM
> To: amibroker@xxxxxxxxxps.com
>
Subject: [amibroker] Re: Close > At least 4 of the previous 5
Closes
>
>
>
> That would give the number of times
within the period that a close
was
> higher than its *immediately*
preceding close. But, it would not
give
> the number of times that
the current close was higher than *all*
> preceding closes for that
period as is being requested.
>
> There may be a more direct way,
but the following would probably do
it
> for you:
>
>
Count = 0;
>
> for (i = 1; i <= 5; i++) {
> Count +=
IIF(Close > Ref(Close, i * -1), 1, 0);
> }
>
> Condition
= Count >= 4;
>
> --- In amibroker@xxxxxxxxx
<mailto:amibroker%40yahoogroups.com>
ps.com,
>
"Gordon Sutherland" <gosuth@>
> wrote:
> >
> >
Try the following:
> >
> > HigherClose = C > Ref(C,-1);
> > HigherThanLast4 = Sum(HigherClose,5) > 4;
> >
Plot(HigherThanLast4,"",colorBlue,2);
> >
> >
Cheers,
> >
> > Gordon Sutherland
> >
>
> -----Original Message-----
> > From: amibroker@xxxxxxxxx
<mailto:amibroker%40yahoogroups.com>
ps.com
>
[mailto:amibroker@yahoogrou
<mailto:amibroker%40yahoogroups.com>
ps.com]
> On
Behalf
> > Of ozzyapeman
> > Sent: Friday, 12 September 2008
12:36 p.m.
> > To: amibroker@xxxxxxxxx
<mailto:amibroker%40yahoogroups.com>
ps.com
> >
Subject: [amibroker] Close > At least 4 of the previous 5 Closes
>
>
> >
> > Quick question - is there a compact way to
write the following:
> >
> > Close > At least 4 of the
previous 5 Closes
> >
> > I know I can write out each case
like:
> >
> > Case_1 =
> > C > ref(C,-1) and C
> ref(C,-2)and C > ref(C,-3)and C > ref(C,-
4)and
> C
>
> > ref(C,-5)
> >
> > Case_2 =
> >
C < ref(C,-1) and C > ref(C,-2)and C > ref(C,-3)and C >
ref(C,-
4)and
> C >
> > ref(C,-5)
> >
>
> etc....
> >
> > and then write if Case _1 or Case _2
or Case_3 or ...
> >
> > But I'm guessing there must be a
simpler way to do this?
> >
> > Any feedback
appreciated.
> >
>