[amibroker] Re: Close > At least 4 of the previous 5 Closes

["ozzyapeman" <zoopfree@xxxxxxxxxxx>]

Thanks guys.


--- In amibroker@xxxxxxxxxxxxxxx, "Paul Ho" <paul.tsho@xxx> wrote:
>
> You are right
> but this one probably will
> c >= ref(percentile(c, 5, 80), -1);
> 
> 
>   _____  
> 
> From: amibroker@xxxxxxxxxxxxxxx [mailto:amibroker@xxxxxxxxxxxxxxx]
On Behalf
> Of Mike
> Sent: Friday, 12 September 2008 12:02 PM
> To: amibroker@xxxxxxxxxxxxxxx
> Subject: [amibroker] Re: Close > At least 4 of the previous 5 Closes
> 
> 
> 
> I haven't tested, but I don't think that that will work. Given a 
> history of:
> 
> 7,7,8,7,10 and current value of 9
> 
> Ref(HHV(C, 5), -1) will give 10, correct?
> 
> The current value of 9 is not greater than 10 so we get false (or 0). 
> But, 9 *is* greater than each of 7,7,8,7 so we actually wanted a true 
> (or 1) here since the current value of 9 is greater than at least 4 of 
> the preceding 5 values.
> 
> Mike
> 
> --- In amibroker@xxxxxxxxx <mailto:amibroker%40yahoogroups.com> ps.com,
> "Paul Ho" <paul.tsho@> wrote:
> >
> > c > ref(hhv(c,5), -1)
> > 
> > 
> > _____ 
> > 
> > From: amibroker@xxxxxxxxx <mailto:amibroker%40yahoogroups.com> ps.com
> [mailto:amibroker@xxxxxxxxx <mailto:amibroker%40yahoogroups.com>
ps.com] 
> On Behalf
> > Of Mike
> > Sent: Friday, 12 September 2008 11:26 AM
> > To: amibroker@xxxxxxxxx <mailto:amibroker%40yahoogroups.com> ps.com
> > Subject: [amibroker] Re: Close > At least 4 of the previous 5 Closes
> > 
> > 
> > 
> > That would give the number of times within the period that a close 
> was 
> > higher than its *immediately* preceding close. But, it would not 
> give 
> > the number of times that the current close was higher than *all* 
> > preceding closes for that period as is being requested.
> > 
> > There may be a more direct way, but the following would probably do 
> it 
> > for you:
> > 
> > Count = 0;
> > 
> > for (i = 1; i <= 5; i++) {
> > Count += IIF(Close > Ref(Close, i * -1), 1, 0);
> > }
> > 
> > Condition = Count >= 4;
> > 
> > --- In amibroker@xxxxxxxxx <mailto:amibroker%40yahoogroups.com> 
> ps.com,
> > "Gordon Sutherland" <gosuth@> 
> > wrote:
> > >
> > > Try the following:
> > > 
> > > HigherClose = C > Ref(C,-1); 
> > > HigherThanLast4 = Sum(HigherClose,5) > 4; 
> > > Plot(HigherThanLast4,"",colorBlue,2); 
> > > 
> > > Cheers,
> > > 
> > > Gordon Sutherland
> > > 
> > > -----Original Message-----
> > > From: amibroker@xxxxxxxxx <mailto:amibroker%40yahoogroups.com> 
> ps.com
> > [mailto:amibroker@xxxxxxxxx <mailto:amibroker%40yahoogroups.com> 
> ps.com] 
> > On Behalf
> > > Of ozzyapeman
> > > Sent: Friday, 12 September 2008 12:36 p.m.
> > > To: amibroker@xxxxxxxxx <mailto:amibroker%40yahoogroups.com> 
> ps.com
> > > Subject: [amibroker] Close > At least 4 of the previous 5 Closes
> > > 
> > > 
> > > Quick question - is there a compact way to write the following:
> > > 
> > > Close > At least 4 of the previous 5 Closes
> > > 
> > > I know I can write out each case like:
> > > 
> > > Case_1 =
> > > C > ref(C,-1) and C > ref(C,-2)and C > ref(C,-3)and C > ref(C,-
> 4)and 
> > C >
> > > ref(C,-5)
> > > 
> > > Case_2 = 
> > > C < ref(C,-1) and C > ref(C,-2)and C > ref(C,-3)and C > ref(C,-
> 4)and 
> > C >
> > > ref(C,-5)
> > > 
> > > etc....
> > > 
> > > and then write if Case _1 or Case _2 or Case_3 or ...
> > > 
> > > But I'm guessing there must be a simpler way to do this?
> > > 
> > > Any feedback appreciated.
> > >
> >
>



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