[amibroker] Re: Close > At least 4 of the previous 5 Closes

["Mike" <sfclimbers@xxxxxxxxx>]

I haven't tested, but I don't think that that will work. Given a 
history of:

7,7,8,7,10 and current value of 9

Ref(HHV(C, 5), -1) will give 10, correct?

The current value of 9 is not greater than 10 so we get false (or 0). 
But, 9 *is* greater than each of 7,7,8,7 so we actually wanted a true 
(or 1) here since the current value of 9 is greater than at least 4 of 
the preceding 5 values.

Mike

--- In amibroker@xxxxxxxxxxxxxxx, "Paul Ho" <paul.tsho@xxx> wrote:
>
> c > ref(hhv(c,5), -1)
> 
> 
>   _____  
> 
> From: amibroker@xxxxxxxxxxxxxxx [mailto:amibroker@xxxxxxxxxxxxxxx] 
On Behalf
> Of Mike
> Sent: Friday, 12 September 2008 11:26 AM
> To: amibroker@xxxxxxxxxxxxxxx
> Subject: [amibroker] Re: Close > At least 4 of the previous 5 Closes
> 
> 
> 
> That would give the number of times within the period that a close 
was 
> higher than its *immediately* preceding close. But, it would not 
give 
> the number of times that the current close was higher than *all* 
> preceding closes for that period as is being requested.
> 
> There may be a more direct way, but the following would probably do 
it 
> for you:
> 
> Count = 0;
> 
> for (i = 1; i <= 5; i++) {
> Count += IIF(Close > Ref(Close, i * -1), 1, 0);
> }
> 
> Condition = Count >= 4;
> 
> --- In amibroker@xxxxxxxxx <mailto:amibroker%40yahoogroups.com> 
ps.com,
> "Gordon Sutherland" <gosuth@> 
> wrote:
> >
> > Try the following:
> > 
> > HigherClose = C > Ref(C,-1); 
> > HigherThanLast4 = Sum(HigherClose,5) > 4; 
> > Plot(HigherThanLast4,"",colorBlue,2); 
> > 
> > Cheers,
> > 
> > Gordon Sutherland
> > 
> > -----Original Message-----
> > From: amibroker@xxxxxxxxx <mailto:amibroker%40yahoogroups.com> 
ps.com
> [mailto:amibroker@xxxxxxxxx <mailto:amibroker%40yahoogroups.com> 
ps.com] 
> On Behalf
> > Of ozzyapeman
> > Sent: Friday, 12 September 2008 12:36 p.m.
> > To: amibroker@xxxxxxxxx <mailto:amibroker%40yahoogroups.com> 
ps.com
> > Subject: [amibroker] Close > At least 4 of the previous 5 Closes
> > 
> > 
> > Quick question - is there a compact way to write the following:
> > 
> > Close > At least 4 of the previous 5 Closes
> > 
> > I know I can write out each case like:
> > 
> > Case_1 =
> > C > ref(C,-1) and C > ref(C,-2)and C > ref(C,-3)and C > ref(C,-
4)and 
> C >
> > ref(C,-5)
> > 
> > Case_2 = 
> > C < ref(C,-1) and C > ref(C,-2)and C > ref(C,-3)and C > ref(C,-
4)and 
> C >
> > ref(C,-5)
> > 
> > etc....
> > 
> > and then write if Case _1 or Case _2 or Case_3 or ...
> > 
> > But I'm guessing there must be a simpler way to do this?
> > 
> > Any feedback appreciated.
> >
>




------------------------------------

Please note that this group is for discussion between users only.

To get support from AmiBroker please send an e-mail directly to 
SUPPORT {at} amibroker.com

For NEW RELEASE ANNOUNCEMENTS and other news always check DEVLOG:
http://www.amibroker.com/devlog/

For other support material please check also:
http://www.amibroker.com/support.html
Yahoo! Groups Links

<*> To visit your group on the web, go to:
    http://groups.yahoo.com/group/amibroker/

<*> Your email settings:
    Individual Email | Traditional

<*> To change settings online go to:
    http://groups.yahoo.com/group/amibroker/join
    (Yahoo! ID required)

<*> To change settings via email:
    mailto:amibroker-digest@xxxxxxxxxxxxxxx 
    mailto:amibroker-fullfeatured@xxxxxxxxxxxxxxx

<*> To unsubscribe from this group, send an email to:
    amibroker-unsubscribe@xxxxxxxxxxxxxxx

<*> Your use of Yahoo! Groups is subject to:
    http://docs.yahoo.com/info/terms/