[amibroker] Re: need any 3 of 4 conditions to be true

["DIMITRIS TSOKAKIS" <TSOKAKIS@xxxxxxxxx>]

Yuki,
As we have already discussed in the past, conditions are binary, 
equal to 1 [when true] and 0 [when false].
Cond1 = whatever;
Cond2 = wherever;
Cond3 = whomever;
Cond4 = however;

filter = Cond1+Cond2+Cond3+Cond4==3;
is equivalent to your " *any* 3 of the 4 above to be true ".
The sum will be
1+1+1+0 or
1+1+0+1 or
1+0+1+1 or
0+1+1+1, in other words always equal to 3.

Dimitris
--- In amibroker@xxxxxxxxxxxxxxx, Yuki Taga <yukitaga@xxxx> wrote:
> If I define four conditions, how can I write a filter statement 
that returns
> issues where *any* 3 of the 4 conditions are true?
> 
> For example:
> 
> Cond1 = whatever;
> Cond2 = wherever;
> Cond3 = whomever;
> Cond4 = however;
> 
> filter = (need *any* 3 of the 4 above to be true);
> 
> I think I could eventually get this done myself, but I suspect the
> result would make a programmer roll on the floor with laughter.  The
> only way I can think of to do it would be *really* long.  There must
> be a compact way of doing this, isn't there?
> 
> Yuki



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