[amibroker] Re: need any 3 of 4 conditions to be true

["johncw_97" <johncw_97@xxxxxxxxx>]

--- In amibroker@xxxxxxxxxxxxxxx, "johncw_97" <johncw_97@xxxx> wrote:
> --- In amibroker@xxxxxxxxxxxxxxx, Yuki Taga <yukitaga@xxxx> wrote:
> > If I define four conditions, how can I write a filter statement 
> that returns
> > issues where *any* 3 of the 4 conditions are true?
> > 
> > For example:
> > 
> > Cond1 = whatever;
> > Cond2 = wherever;
> > Cond3 = whomever;
> > Cond4 = however;
> > 
> > filter = (need *any* 3 of the 4 above to be true);
> > 
> I believe that "filter=Nz(Cond1)+Nz(Cond2)+Nz(Cond3)+Nz(Cond4)>=3;"
> would work. [...]
Should have bracketed the summation
filter=(Nz(Cond1)+Nz(Cond2)+Nz(Cond3)+Nz(Cond4))>=3;




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