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Re: [amibroker] Re: need any 3 of 4 conditions to be true



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Hi DIMITRIS,

My last response before I go out the door, or I'll never get up to
the top of the mountain today.  ^_^

Thursday, September 23, 2004, 4:10:29 AM, you wrote:

DT> Yuki, As we have already discussed in the past, conditions are
DT> binary,  equal to 1 [when true] and 0 [when false]. Cond1 =
DT> whatever; Cond2 = wherever; Cond3 = whomever; Cond4 = however;

DT> filter = Cond1+Cond2+Cond3+Cond4==3;
DT> is equivalent to your " *any* 3 of the 4 above to be true ".
DT> The sum will be
DT> 1+1+1+0 or
DT> 1+1+0+1 or
DT> 1+0+1+1 or
DT> 0+1+1+1, in other words always equal to 3.

This is the type of compactness I was looking for, but 4 true would
also be good of course, so I assume:

filter = Cond1+Cond2+Cond3+Cond4 >= 3;

is okay, too?  (I should not want to filter out either 3 or 4.)

Yuki



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