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[amibroker] Re: need any 3 of 4 conditions to be true



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--- In amibroker@xxxxxxxxxxxxxxx, Yuki Taga <yukitaga@xxxx> wrote:
> If I define four conditions, how can I write a filter statement 
that returns
> issues where *any* 3 of the 4 conditions are true?
> 
> For example:
> 
> Cond1 = whatever;
> Cond2 = wherever;
> Cond3 = whomever;
> Cond4 = however;
> 
> filter = (need *any* 3 of the 4 above to be true);
> 
I believe that "filter=Nz(Cond1)+Nz(Cond2)+Nz(Cond3)+Nz(Cond4)>=3;"
would work. If any CondX is undefined then the sum of them
would also be undefined. example: if one condition is MA(C,300)<C
then the first 299 bars would not be 0 or 1.

> I think I could eventually get this done myself, but I suspect the
> result would make a programmer roll on the floor with laughter.  
The
> only way I can think of to do it would be *really* long.  There 
must
> be a compact way of doing this, isn't there?
> 
> Yuki



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