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Try using Sum(cond1 and cond2 and cond3 and cond4,ndays)>=3;
----- Original Message -----
From: Yuki Taga
To: amibroker@xxxxxxxxxxxxxxx
Sent: Wednesday, September 22, 2004 8:20 AM
Subject: [amibroker] need any 3 of 4 conditions to be true
If I define four conditions, how can I write a filter statement that returns
issues where *any* 3 of the 4 conditions are true?
For example:
Cond1 = whatever;
Cond2 = wherever;
Cond3 = whomever;
Cond4 = however;
filter = (need *any* 3 of the 4 above to be true);
I think I could eventually get this done myself, but I suspect the
result would make a programmer roll on the floor with laughter. The
only way I can think of to do it would be *really* long. There must
be a compact way of doing this, isn't there?
Yuki
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