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<FONT face=Arial color=#0000ff
size=2>Thank you DT, as usual your reply is not only informative but
entertaining :-) an 8x improvement in speed would be just fine. If my own
solution is general I will post it.
<FONT face=Arial color=#0000ff
size=2>
<FONT face=Arial color=#0000ff
size=2>I think I received enough ideas to try a few things, solving
a small challenge with your owninput is half the fun and a better way to learn.
<FONT face=Arial color=#0000ff
size=2>
<FONT face=Arial color=#0000ff
size=2>Thanks everybody and have a great day!
<FONT face=Arial color=#0000ff
size=2>herman
<FONT face=Tahoma
size=2>-----Original Message-----From: DIMITRIS TSOKAKIS
[mailto:TSOKAKIS@xxxxxxxxx]Sent: January 29, 2004 2:16
AMTo: amibroker@xxxxxxxxxxxxxxxSubject: [amibroker] Re:
Successive Approximation in aflHerman,my method
is a bit different.I begin with the 1st digit accuracy [10 steps maximum,
1.0 to 1.9] and localize1.4<sqrt(2)<1.5Then, for the 2nd
digit, 10 steps [maximum] again to obtain1.41<sqrt(2)<1.42and so
on.In the average, I need 5 steps per digit and, for a 3-decimal
accuracy it will take about5*5*5=125 steps instead of the normal
1000.Archimedes, the copyright of the method, was not working with
decimals.For some reason [not explained anywhere], his first
choice was the sevenths of the unity 1/7, 2/7, 3/7 etc .So, in his
famous "Measurement of a Circle", he proves
that3+1/7>pi>3+10/71As you see, he slightly increases the
denominator [he does not increase the numerator].There are some
obscure statements, he never explained, for example, how did he came
to the [useful approximation]265/153<sqrt(3)<1351/780 [!!!].but,
we can not always have what we want...Dimitris Tsokakis--- In
amibroker@xxxxxxxxxxxxxxx, "Herman vandenBergen" <psytek@xxxx>
wrote:> thanks DT, I have to study your code but I think you have
the general idea.> I have an impossible formula to transform (it
contains HHV and LLVs,> stochastic mutation) and want to find the x
that would give me the given y.> Right now I linearly increment x
untill I hit my y-target, this is awfully> slow.>
> like y = function(x); // y ranges 0-100 and I want 2 decimal places
for x> that gives me a given y> > I thought cutting
the range in half, see whether it is greater or less, cut> the
result in half again, etc. I am not a math guy but I have used>
AD-converters that worked like that and what we can do in hardware we can
do> in software :-)> > thanks for the starter DT,>
herman> > > > > -----Original
Message-----> From: DIMITRIS TSOKAKIS [mailto:TSOKAKIS@xxxx]>
Sent: January 28, 2004 9:18 PM> To: amibroker@xxxxxxxxxxxxxxx>
Subject: [amibroker] Re: Successive Approximation in afl> >
> Herman,> You mean a procedure like
this> > a=1;b=2;z=0;>
st0=0.1;st1=0.01;st2=0.01;> //1st
decimal> for(i=a;i<b;i=i+st0)>
{> if(i^2<2 AND (i+st0)^2>2)>
z=i;> }> //2nd
decimal> for(i=z;i<z+st0;i=i+st1)>
{> if(i^2<2 AND (i+st1)^2>2)>
z=i;> }> //...etc>
Plot(z,"sqrt(2)",1,1);> > to find sqrt(2) without
using all the values from 1 to 2 ?> Dimitris
Tsokakis> --- In amibroker@xxxxxxxxxxxxxxx, "Herman
vandenBergen" <psytek@xxxx>>
wrote:> > Hello,>
>> > has anybody come accross a successive
approximation routine in afl?> Or>
> perhaps js?> >> >
thanks,> > herman> > >
> Send BUG REPORTS to bugs@xxxx> Send
SUGGESTIONS to suggest@xxxx>
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