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Re: [Metastockusers] Re: formula question



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Tom,
I would have done so, but for the last couple of 
days, the Yahoo groups are blocked in our part of the world.
I cannot even visit the <A 
href="">candlestrength 
group, of which I am a moderator, because of some technical problem with 
Yahoo.
The only way I can keep in touch with the Yahoo 
world is through emails. That is why I had requested the indulgence of a 
repost.
DusantChief Architect<A 
href="">http://www.candlestrength.com/
 
<BLOCKQUOTE dir=ltr 
>
  ----- Original Message ----- 
  <DIV 
  >From: 
  Tom 
  Sprunger 
  To: <A 
  title=Metastockusers@xxxxxxxxxxxxxxx 
  href="">Metastockusers@xxxxxxxxxxxxxxx 
  
  Sent: Wednesday, July 21, 2004 5:44 
  PM
  Subject: Re: [Metastockusers] Re: formula 
  question
  
  "Maybe the original enquirer could 
  be so kind to elaborate on what this code is supposed to 
  do."
  Dusant, if you read the thread, I posted  
  an explanation of what the code is supposed to do.
  Follow the thread.
   
  Tom
  <BLOCKQUOTE 
  >
    ----- Original Message ----- 
    <DIV 
    >From: 
    <A title=dusant@xxxxxxxxxxxxxxxxxx 
    href="">Dusant 
    To: <A 
    title=Metastockusers@xxxxxxxxxxxxxxx 
    href="">Metastockusers@xxxxxxxxxxxxxxx 
    
    Sent: Wednesday, July 21, 2004 3:19 
    AM
    Subject: Re: [Metastockusers] Re: 
    formula question
    
    Brute force is fine. :) except there seems 
    something missing.
    There should be a seeding number to begin 
    with, to bring it down to starting point or else the calculated values would 
    shoot though the roof, as we keep on adding the 1/3 values over 20 
    periods.
    Maybe the original enquirer could be so kind 
    to elaborate on what this code is supposed to do.
    DusantChief Architect<A 
    href="">http://www.candlestrength.com/
    <BLOCKQUOTE 
    >
      ----- Original Message ----- 
      <DIV 
      >From: 
      <A title=bellamy_29m@xxxxxxxxx 
      href="">bellamy_29m@xxxxxxxxx 
      To: <A 
      title=Metastockusers@xxxxxxxxxxxxxxx 
      href="">Metastockusers@xxxxxxxxxxxxxxx 
      
      Sent: Tuesday, July 20, 2004 5:37 
      PM
      Subject: [Metastockusers] Re: formula 
      question
      When neat coding fails, try brute 
      force:n:=20;((n)-(n+1)/3)*C+((n-1)-(n+1)/3)*Ref(C,n-(n+1))+((n-2)-(n+1)/3)*Ref(C,n-(n+2))+((n-3)-(n+1)/3)*Ref(C,n-(n+3))+((n-4)-(n+1)/3)*Ref(C,n-(n+4))+((n-5)-(n+1)/3)*Ref(C,n-(n+5))+((n-6)-(n+1)/3)*Ref(C,n-(n+6))+((n-7)-(n+1)/3)*Ref(C,n-(n+7))+((n-8)-(n+1)/3)*Ref(C,n-(n+8))+((n-9)-(n+1)/3)*Ref(C,n-(n+9))+((n-10)-(n+1)/3)*Ref(C,n-(n+10))+((n-11)-(n+1)/3)*Ref(C,n-(n+11))+((n-12)-(n+1)/3)*Ref(C,n-(n+12))+((n-13)-(n+1)/3)*Ref(C,n-(n+13))+((n-14)-(n+1)/3)*Ref(C,n-(n+14))+((n-15)-(n+1)/3)*Ref(C,n-(n+15))+((n-16)-(n+1)/3)*Ref(C,n-(n+16))+((n-17)-(n+1)/3)*Ref(C,n-(n+17))+((n-18)-(n+1)/3)*Ref(C,n-(n+18))+((n-19)-(n+1)/3)*Ref(C,n-(n+19));wabbit 
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