> >>>
40yahoogroups.com>,
> >>> "Louis P."
> >>> > > <rockprog80@> wrote:
> >>> > > >
> >>> > > > Hi,
> >>> > > >
> >>> > > > @Tony:Sorry I thought gradient was the good word. Maybe I
meant
> >>> > > angle, or
> >>> > > > degree? I want a LR slope of approx. 30-50 degrees. How
can I do
> >>> that?
> >>> > > > @gp_sydney: I need to go to work, but will check this
tomorrow or
> >>> > > Monday. I
> >>> > > > looked very quickly and was wondering where in that
formula can I
> >>> > > determine
> >>> > > > how steep the slope will be. That would help a lot!
> >>> > > >
> >>> > > > Thank you you two a lot!
> >>> > > >
> >>> > > > Louis
> >>> > > >
> >>> > > >
> >>> > > >
> >>> > > > 2008/9/20 gp_sydney <gp.investment@>
> >>> > > >
> >>> > > > > Sorry, a couple of typos in the formula. It should be:
> >>> > > > >
> >>> > > > >
> >>> > > > > n = HHVBars(High, periods);
> >>> > > > > avX = MA(x, n);
> >>> > > > > avY = MA(y, n);
> >>> > > > > avXY = MA(x*y, n);
> >>> > > > > avXX = MA(x*x, n);
> >>> > > > >
> >>> > > > > b = (avXY - avX*avY) / (avXX - avX*avX);
> >>> > > > > a = avY - b*avX;
> >>> > > > >
> >>> > > > > GP
> >>> > > > >
> >>> > > > >
> >>> > > > > --- In
amibroker@xxxxxxxxxxxxxxx
<amibroker%
40yahoogroups.com>
> >>> <amibroker%
40yahoogroups.com><amibroker%
> >>>
> >>> > >
40yahoogroups.com>,
> >>> > >
> >>> > > > > "gp_sydney" <gp.investment@> wrote:
> >>> > > > > >
> >>> > > > > > Louis,
> >>> > > > > >
> >>> > > > > > I gather you want to use regression to get a best-fit line
> >>> from the
> >>> > > > > > most-recent HHV, not just draw a line between the end
points.
> >>> > > From my
> >>> > > > > > understanding of regression though, which isn't a lot, I
> >>> gather that
> >>> > > > > > such a line may not actually pass through either end
point, so
> >>> > > may not
> >>> > > > > > go "from the HHV" exactly or end at the current bar
exactly
> >>> (to get
> >>> > > > > > that, just draw a line between those two points as
previously
> >>> > > > > > mentioned). Once you have the line though, you could
offset it
> >>> > > > > > vertically to get it to pass exactly through the HHV or
> >>> current bar
> >>> > > > > > (but not both of course).
> >>> > > > > >
> >>> > > > > > From a response Tomasz gave you in another thread
about how to
> >>> > > > > > calculate Rsquared without a loop:
> >>> > > > > >
> >>> > > > > >
http://finance.groups.yahoo.com/group/amibroker/message/129392
> >>> > > > > >
> >>> > > > > > you can similarly do the regression itself. According to
> >>> Tomasz,
> >>> > > > > > LinRegSlope already accepts variable periods (ie. arrays),
> >>> so to get
> >>> > > > > > the slope you should be able to just use that
function. Or to
> >>> > > > > > calculate both coefficients yourself, then something
like this
> >>> > > (based
> >>> > > > > > on the formula given at
http://www.educalc.net/2104083.page):
> >>> > > > > >
> >>> > > > > > n = HHVBars(High, periods);
> >>> > > > > > avX = MA(x, n);
> >>> > > > > > avY = MA(y, n);
> >>> > > > > > avXY = MA(x*y, n);
> >>> > > > > > axXX = MA(x*x, n);
> >>> > > > > >
> >>> > > > > > b = (avXY - avX*avY) / (avXX - avX*avX);
> >>> > > > > > a = axY - b*avX;
> >>> > > > > >
> >>> > > > > > Hopefully I've got that right (I haven't tested it).
The line
> >>> > > formula
> >>> > > > > > is then:
> >>> > > > > >
> >>> > > > > > line = a + b*x;
> >>> > > > > >
> >>> > > > > > The slope is 'b' and the intercept 'a'. The slope is in
> >>> dollars per
> >>> > > > > > bar. I'm not sure what you want by a percentage slope
> >>> though, as the
> >>> > > > > > 'x' and 'y' axes are in completely different units.
> >>> > > > > >
> >>> > > > > > Also note that the calculated lines would only be
straight on a
> >>> > > linear
> >>> > > > > > price scale (if they were plotted). If you use semi-log,
> >>> then the
> >>> > > > > > formula for a straight line is different - and how to do
> >>> regression
> >>> > > > > > for it would take some figuring out.
> >>> > > > > >
> >>> > > > > > Hope this helps.
> >>> > > > > >
> >>> > > > > > Regards,
> >>> > > > > > GP
> >>> > > > > >
> >>> > > > > >
> >>> > > > > > --- In
amibroker@xxxxxxxxxxxxxxx
<amibroker%
40yahoogroups.com>
> >>> <amibroker%
40yahoogroups.com><amibroker%
> >>>
> >>> > >
40yahoogroups.com>,
> >>> > >
> >>> > > "Louis
> >>> > > > > P." <rockprog80@> wrote:
> >>> > > > > > >
> >>> > > > > > > Hi,
> >>> > > > > > >
> >>> > > > > > > I need the gradient of the slope, and for each bar. This
> >>> is where
> >>> > > > > it is
> >>> > > > > > > difficult...
> >>> > > > > > >
> >>> > > > > > > Thanks,
> >>> > > > > > >
> >>> > > > > > > Louis
> >>> > > > > > >
> >>> > > > > > > 2008/9/19 Tony Grimes <Tonez.Email@>
> >>> > > > > > >
> >>> > > > > > > > Louis,
> >>> > > > > > > >
> >>> > > > > > > > If your looking for the slope & difference between
HHV of
> >>> 20
> >>> > > bars
> >>> > > > > > & the
> >>> > > > > > > > current close, all you should need is this:
> >>> > > > > > > >
> >>> > > > > > > > Pds=20;
> >>> > > > > > > >
> >>> > > > > > > > LastHighBar = HHVBars(High, Pds);
> >>> > > > > > > > LastHighVal = HHV(High, Pds);
> >>> > > > > > > >
> >>> > > > > > > > Slope = IIf(LastHighBar,(Close - LastHighVal) /
> >>> LastHighBar,0);
> >>> > > > > > > > CloseDiff = Close - Ref(Close, -LastHighBar);
> >>> > > > > > > >
> >>> > > > > > > >
> >>> > > > > > > > On Fri, Sep 19, 2008 at 4:51 PM, Louis P.
<rockprog80@>
> >>> wrote:
> >>> > > > > > > >
> >>> > > > > > > >> Hi Tony,
> >>> > > > > > > >>
> >>> > > > > > > >> Thank you a lot for your response. I'm still very
weak
> >>> with
> >>> > > > > > loops. Last
> >>> > > > > > > >> time experimented with one, I had to reboot my
> >>> computer! :) So
> >>> > > > > > do you know
> >>> > > > > > > >> how such a loop could work? And if I run, let's say 2
> >>> minutes
> >>> > > > > > bar for one
> >>> > > > > > > >> year, wouldn't that be really really long to deal
with?
> >>> I have
> >>> > > > > > PIV with 1.5
> >>> > > > > > > >> GHz ram.
> >>> > > > > > > >>
> >>> > > > > > > >> I am looking for a line that ends at each bar and
that
> >>> starts
> >>> > > > > > from the HHV
> >>> > > > > > > >> of 20 bars, and I want to do things with this
bar: e.g.
> >>> compare
> >>> > > > > > the closes
> >>> > > > > > > >> between current bar and the HHV to the bar and
> >>> establish the
> >>> > > > > > gradient of
> >>> > > > > > > >> that linear regression bar for each bar.
> >>> > > > > > > >>
> >>> > > > > > > >> Thanks a lot!
> >>> > > > > > > >>
> >>> > > > > > > >> Louis
> >>> > > > > > > >>
> >>> > > > > > > >> 2008/9/19 Tony Grimes <Tonez.Email@>
> >>> > > > > > > >>
> >>> > > > > > > >>> Hi Louis,
> >>> > > > > > > >>>
> >>> > > > > > > >>> A loop will work, but how slow - it depends
(Speed of
> >>> your
> >>> > > > > computer,
> >>> > > > > > > >>> number of bars loaded, how many loops your using
etc...).
> >>> > > > > > Without seeing
> >>> > > > > > > >>> what your actually looking for (The end result), I
> >>> think you
> >>> > > > > > could do it
> >>> > > > > > > >>> with one loop, with only one pass through the loop.
> >>> The speed
> >>> > > > > > should be OK.
> >>> > > > > > > >>>
> >>> > > > > > > >>> Good Luck.
> >>> > > > > > > >>>
> >>> > > > > > > >>> Tony
> >>> > > > > > > >>>
> >>> > > > > > > >>> On Fri, Sep 19, 2008 at 2:47 PM, Louis P.
> >>> <rockprog80@> wrote:
> >>> > > > > > > >>>
> >>> > > > > > > >>>> Hi Tony,
> >>> > > > > > > >>>>
> >>> > > > > > > >>>> Thanks for the tips. Basically, I'd need a loop and
> >>> use it on
> >>> > > > > > each and
> >>> > > > > > > >>>> every bar of the array to determine the LR, right?
> >>> > > > > > > >>>>
> >>> > > > > > > >>>> That will slow down my computer a lot, don't
you think?
> >>> > > > > > > >>>>
> >>> > > > > > > >>>> Thanks,
> >>> > > > > > > >>>>
> >>> > > > > > > >>>> Louis
> >>> > > > > > > >>>>
> >>> > > > > > > >>>> 2008/9/16 Tony Grimes <Tonez.Email@>
> >>> > > > > > > >>>>
> >>> > > > > > > >>>>> SelectedValue takes an array ( of numbers) and
returns
> >>> a
> >>> > > > > single
> >>> > > > > > > >>>>> number based on the bar that is selected in
the chart.
> >>> > > > > > > >>>>>
> >>> > > > > > > >>>>> The first formula worked because SelectedValue was
> >>> > > giving you a
> >>> > > > > > > >>>>> number.
> >>> > > > > > > >>>>>
> >>> > > > > > > >>>>> Look at it this way: Array --> SelectedValue --->
> >>> Number.
> >>> > > > > > > >>>>>
> >>> > > > > > > >>>>> Remove SelectedValue: Array---->Array.
> >>> > > > > > > >>>>>
> >>> > > > > > > >>>>> You can draw a line with single numbers, but not
> >>> arrays.
> >>> > > > > > > >>>>>
> >>> > > > > > > >>>>> You can always use a loop.
> >>> > > > > > > >>>>>
> >>> > > > > > > >>>>> You might want to read: Understanding how AFL
works,
> >>> in the
> >>> > > > > > Amibroker
> >>> > > > > > > >>>>> users guide. Until you really understand AFL &
array
> >>> > > > > > processing, you are
> >>> > > > > > > >>>>> going to keep running into these problems, which
> >>> will just
> >>> > > > > > slow you down.
> >>> > > > > > > >>>>>
> >>> > > > > > > >>>>>
> >>> > > > > > > >>>>> On Tue, Sep 16, 2008 at 10:34 PM, Louis P.
> >>> > > <rockprog80@>wrote:
> >>> > > > > > > >>>>>
> >>> > > > > > > >>>>>> Hi Tony,
> >>> > > > > > > >>>>>>
> >>> > > > > > > >>>>>> Why was the first formula working (the one with
> >>> > > > > > selectedvalue) and not
> >>> > > > > > > >>>>>> the second one? Why simply deleting the
> >>> "selectedvalue"
> >>> > > > > > makes it an array
> >>> > > > > > > >>>>>> that will not be accept in "linearray"?
> >>> > > > > > > >>>>>>
> >>> > > > > > > >>>>>> Is there any way to draw a line without using
> >>> lastvalue or
> >>> > > > > > > >>>>>> selectedvalue? Do I need to use a loop?
> >>> > > > > > > >>>>>>
> >>> > > > > > > >>>>>> Thanks,
> >>> > > > > > > >>>>>>
> >>> > > > > > > >>>>>> Louis
> >>> > > > > > > >>>>>>
> >>> > > > > > > >>>>>> 2008/9/16 Tony Grimes <Tonez.Email@>
> >>> > > > > > > >>>>>>
> >>> > > > > > > >>>>>>> Louis,
> >>> > > > > > > >>>>>>>
> >>> > > > > > > >>>>>>> All of the variables you are creating for the
> >>> LineArray
> >>> > > > > > function are
> >>> > > > > > > >>>>>>> arrays themselves. Although LineArray
generates an
> >>> > > array, it
> >>> > > > > > does not accept
> >>> > > > > > > >>>>>>> any arrays as inputs. Additionally, your error
> >>> message was
> >>> > > > > > probably
> >>> > > > > > > >>>>>>> different. It probably went from complaining
about
> >>> > > argument
> >>> > > > > > #4 having the
> >>> > > > > > > >>>>>>> incorrect type (which you corrected) to argument
> >>> #3 having
> >>> > > > > > the incorrect
> >>> > > > > > > >>>>>>> type.
> >>> > > > > > > >>>>>>>
> >>> > > > > > > >>>>>>> On Tue, Sep 16, 2008 at 9:10 PM, Louis P.
> >>> > > <rockprog80@>wrote:
> >>> > > > > > > >>>>>>>
> >>> > > > > > > >>>>>>>> Hi,
> >>> > > > > > > >>>>>>>>
> >>> > > > > > > >>>>>>>> Thank you for your help.
> >>> > > > > > > >>>>>>>>
> >>> > > > > > > >>>>>>>> @Ara:
> >>> > > > > > > >>>>>>>>
> >>> > > > > > > >>>>>>>> If in
> >>> > > > > > > >>>>>>>>
> >>> > > > > > > >>>>>>>> barhh1 = HHVBars( High, Periods ) ;
> >>> > > > > > > >>>>>>>> bi1 = BarIndex();
> >>> > > > > > > >>>>>>>> y11 = LinearReg( C, barhh1 ) ;
> >>> > > > > > > >>>>>>>> y01 = LinRegIntercept( C, barhh1 ) ;
> >>> > > > > > > >>>>>>>> sl1 = LineArray( bi1-barhh1+0, y01, bi1,
y11, 0,
> >>> True );
> >>> > > > > > > >>>>>>>>
> >>> > > > > > > >>>>>>>> I replace
> >>> > > > > > > >>>>>>>>
> >>> > > > > > > >>>>>>>> sl1 = LineArray( bi1-barhh1+0, y01, bi1,
y11, 0,
> >>> True );
> >>> > > > > > > >>>>>>>>
> >>> > > > > > > >>>>>>>> by
> >>> > > > > > > >>>>>>>>
> >>> > > > > > > >>>>>>>> sl1 = LineArray( bi1-barhh1+0, y01, bi1,
> >>> > > LastValue(y11), 0,
> >>> > > > > > True
> >>> > > > > > > >>>>>>>> );
> >>> > > > > > > >>>>>>>>
> >>> > > > > > > >>>>>>>> I still have the same error message. I
don't know
> >>> from
> >>> > > > > > where it is
> >>> > > > > > > >>>>>>>> coming.. unfortunately!
> >>> > > > > > > >>>>>>>>
> >>> > > > > > > >>>>>>>>
> >>> > > > > > > >>>>>>>> @gp_sydney:
> >>> > > > > > > >>>>>>>>
> >>> > > > > > > >>>>>>>> That was a typo, you are right; I arranged
that by
> >>> > > adding a
> >>> > > > > > 1. But
> >>> > > > > > > >>>>>>>> still, the problem remains: the last line does
> >>> not work.
> >>> > > > > > > >>>>>>>>
> >>> > > > > > > >>>>>>>> One day, I asked support if I needed a loop
to do
> >>> such LR
> >>> > > > > > and they
> >>> > > > > > > >>>>>>>> said I should not need one.
> >>> > > > > > > >>>>>>>>
> >>> > > > > > > >>>>>>>> Here is the original code:
> >>> > > > > > > >>>>>>>>
> >>> > > > > > > >>>>>>>> barhh = SelectedValue( HHVBars( High,
Periods ) );
> >>> > > > > > > >>>>>>>> bi = SelectedValue( BarIndex() );
> >>> > > > > > > >>>>>>>> y1 = SelectedValue( LinearReg( C, barhh ) );
> >>> > > > > > > >>>>>>>> y0 = SelectedValue( LinRegIntercept( C,
barhh ) );
> >>> > > > > > > >>>>>>>> sl = LineArray( bi-barhh+0, y0, bi, y1, 0,
True );
> >>> > > > > > > >>>>>>>>
> >>> > > > > > > >>>>>>>> What I want to do is simply eliminate the
> >>> "selectedvalue"
> >>> > > > > > part and
> >>> > > > > > > >>>>>>>> use the code not only for the selected data but
> >>> for the
> >>> > > > > > whole data. I want
> >>> > > > > > > >>>>>>>> to be able to draw a line from each HHV to each
> >>> bar and
> >>> > > > > > then work with the
> >>> > > > > > > >>>>>>>> result.
> >>> > > > > > > >>>>>>>>
> >>> > > > > > > >>>>>>>> If it can't be done without a loop, I feel like
> >>> I'll be
> >>> > > > > > lost in time
> >>> > > > > > > >>>>>>>> again; last time I tried to run a loop on my
> >>> computer it
> >>> > > > > > freezed and after 2
> >>> > > > > > > >>>>>>>> minutes I decided to shut down AB...
> >>> > > > > > > >>>>>>>>
> >>> > > > > > > >>>>>>>>
> >>> > > > > > > >>>>>>>> Thanks for the help,
> >>> > > > > > > >>>>>>>>
> >>> > > > > > > >>>>>>>> Louis
> >>> > > > > > > >>>>>>>>
> >>> > > > > > > >>>>>>>>
> >>> > > > > > > >>>>>>>>
> >>> > > > > > > >>>>>>>>
> >>> > > > > > > >>>>>>>>
> >>> > > > > > > >>>>>>>>
> >>> > > > > > > >>>>>>>>
> >>> > > > > > > >>>>>>>> 2008/9/16 gp_sydney <gp.investment@>
> >>> > > > > > > >>>>>>>>
> >>> > > > > > > >>>>>>>>> As Ara said, in the shown code snippet you
don't
> >>> have
> >>> > > > > > "barhh"
> >>> > > > > > > >>>>>>>>> defined,
> >>> > > > > > > >>>>>>>>> only "barhh1".
> >>> > > > > > > >>>>>>>>>
> >>> > > > > > > >>>>>>>>> Beyond that, you have the same issue I
mentioned
> >>> > > > > > originally, that
> >>> > > > > > > >>>>>>>>> the
> >>> > > > > > > >>>>>>>>> linear regression functions and LineArray
> >>> function take
> >>> > > > > scalar
> >>> > > > > > > >>>>>>>>> values
> >>> > > > > > > >>>>>>>>> (ie. single numbers) as parameters, not
arrays.
> >>> > > > > > > >>>>>>>>>
> >>> > > > > > > >>>>>>>>> I gather you're trying to create a line
from the
> >>> > > > > > most-recent HHV
> >>> > > > > > > >>>>>>>>> value
> >>> > > > > > > >>>>>>>>> using the subsequent close data for every
bar on
> >>> the
> >>> > > > > > chart. As I
> >>> > > > > > > >>>>>>>>> don't
> >>> > > > > > > >>>>>>>>> think the linear regression functions can take
> >>> arrays
> >>> > > > > for the
> >>> > > > > > > >>>>>>>>> period,
> >>> > > > > > > >>>>>>>>> I think you'd need to use a loop and do
the linear
> >>> > > > > regression
> >>> > > > > > > >>>>>>>>> yourself
> >>> > > > > > > >>>>>>>>> at each bar (you could call the array
functions
> >>> > > within the
> >>> > > > > > loop,
> >>> > > > > > > >>>>>>>>> but
> >>> > > > > > > >>>>>>>>> since they fill a whole array each time, they
> >>> would do a
> >>> > > > > > lot of
> >>> > > > > > > >>>>>>>>> unnecessary work). If you do that yourself
> >>> inside the
> >>> > > > > > loop, then at
> >>> > > > > > > >>>>>>>>> each bar you'd have scalar 'x' and 'y'
values to
> >>> > > calculate
> >>> > > > > > the line
> >>> > > > > > > >>>>>>>>> slope and so on.
> >>> > > > > > > >>>>>>>>>
> >>> > > > > > > >>>>>>>>> For what it's worth, the BarIndex function
> >>> simply gives
> >>> > > > > > you the bar
> >>> > > > > > > >>>>>>>>> number. It provides a way of using the
current bar
> >>> > > number
> >>> > > > > > in array
> >>> > > > > > > >>>>>>>>> formula.
> >>> > > > > > > >>>>>>>>>
> >>> > > > > > > >>>>>>>>> Regards,
> >>> > > > > > > >>>>>>>>> GP
> >>> > > > > > > >>>>>>>>>
> >>> > > > > > > >>>>>>>>>
> >>> > > > > > > >>>>>>>>> --- In
> >>> > >
amibroker@xxxxxxxxxxxxxxx <amibroker%
40yahoogroups.com>
<amibroker%
> >>>
40yahoogroups.com><amibroker%
> >>> > >
40yahoogroups.com>
> >>> > > > > > <amibroker%
40yahoogroups.com>,
> >>> > > > > > > >>>>>>>>> "Louis P." <rockprog80@> wrote:
> >>> > > > > > > >>>>>>>>> >
> >>> > > > > > > >>>>>>>>> > Hi,
> >>> > > > > > > >>>>>>>>> >
> >>> > > > > > > >>>>>>>>> > Sorry, You can replace "periods" by 50
if you
> >>> wish. I
> >>> > > > > > just forgot
> >>> > > > > > > >>>>>>>>> to
> >>> > > > > > > >>>>>>>>> > include that.
> >>> > > > > > > >>>>>>>>> >
> >>> > > > > > > >>>>>>>>> > barhh1 = HHVBars( High, *50* ) ;
> >>> > > > > > > >>>>>>>>> > bi1 = BarIndex() ;
> >>> > > > > > > >>>>>>>>> > y11 = LinearReg( C, barhh ) ;
> >>> > > > > > > >>>>>>>>> > y01 = LinRegIntercept( C, barhh ) ;
> >>> > > > > > > >>>>>>>>> > sl1 = LineArray( bi1-barhh1+0, y01, bi1,
y11, 0,
> >>> > > True );
> >>> > > > > > > >>>>>>>>> >
> >>> > > > > > > >>>>>>>>> > Still, it is not working, even if barhh1 is
> >>> defined...
> >>> > > > > > > >>>>>>>>> >
> >>> > > > > > > >>>>>>>>> > Louis
> >>> > > > > > > >>>>>>>>> >
> >>> > > > > > > >>>>>>>>> > 2008/9/16 Ara Kaloustian <ara1@>
> >>> > > > > > > >>>>>>>>> >
> >>> > > > > > > >>>>>>>>> > > y11 and y01 use "barhh" which is not
defined.
> >>> > > > > > > >>>>>>>>> > >
> >>> > > > > > > >>>>>>>>> > > You have defined "barhh1"
> >>> > > > > > > >>>>>>>>> > >
> >>> > > > > > > >>>>>>>>> > >
> >>> > > > > > > >>>>>>>>> > >
> >>> > > > > > > >>>>>>>>> > > ----- Original Message -----
> >>> > > > > > > >>>>>>>>> > > *From:* Louis P. <rockprog80@>
> >>> > > > > > > >>>>>>>>> > > *To:*
> >>> > >
amibroker@xxxxxxxxxxxxxxx <amibroker%
40yahoogroups.com>
<amibroker%
> >>>
40yahoogroups.com><amibroker%
> >>> > >
40yahoogroups.com>
> >>> > > > > > <amibroker%
40yahoogroups.com>
> >>> > > > > > > >>>>>>>>> > > *Sent:* Tuesday, September 16, 2008
2:46 PM
> >>> > > > > > > >>>>>>>>> > > *Subject:* [amibroker] What is wrong?
> >>> > > > > > > >>>>>>>>> > >
> >>> > > > > > > >>>>>>>>> > > Hi,
> >>> > > > > > > >>>>>>>>> > >
> >>> > > > > > > >>>>>>>>> > > What is wrong in the following formula?
> >>> > > > > > > >>>>>>>>> > >
> >>> > > > > > > >>>>>>>>> > > barhh1 = HHVBars( High, Periods ) ;
> >>> > > > > > > >>>>>>>>> > > bi1 = BarIndex() ;
> >>> > > > > > > >>>>>>>>> > > y11 = LinearReg( C, barhh ) ;
> >>> > > > > > > >>>>>>>>> > > y01 = LinRegIntercept( C, barhh ) ;
> >>> > > > > > > >>>>>>>>> > > sl1 = LineArray( bi1-barhh1+0, y01,
bi1, y11,
> >>> 0,
> >>> > > True );
> >>> > > > > > > >>>>>>>>> > >
> >>> > > > > > > >>>>>>>>> > >
> >>> > > > > > > >>>>>>>>> > > Thanks,
> >>> > > > > > > >>>>>>>>> > >
> >>> > > > > > > >>>>>>>>> > > Louis
> >>> > > > > > > >>>>>>>>> > >
> >>> > > > > > > >>>>>>>>> > > p.s. There was "Selectedvalue" in the
first
> >>> four
> >>> > > lines
> >>> > > > > > but I
> >>> > > > > > > >>>>>>>>> don't
> >>> > > > > > > >>>>>>>>> want to
> >>> > > > > > > >>>>>>>>> > > plot it on the chart based on where I
am on
> >>> that
> >>> > > > > > chart, but
> >>> > > > > > > >>>>>>>>> simply
> >>> > > > > > > >>>>>>>>> set the
> >>> > > > > > > >>>>>>>>> > > variable so I can use the stuff later.
> >>> > > > > > > >>>>>>>>> > >
> >>> > > > > > > >>>>>>>>> > >
> >>> > > > > > > >>>>>>>>> > >
> >>> > > > > > > >>>>>>>>> >
> >>> > > > > > > >>>>>>>>>
> >>> > > > > > > >>>>>>>>>
> >>> > > > > > > >>>>>>>>
> >>> > > > > > > >>>>>>>
> >>> > > > > > > >>>>>>
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