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RE: [amibroker] Re: Running total array help



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Nick,

 

The following logic should work:

 

newarray[0] = myarray[0];

for (i=1; i<BarCount; i++)

{

newarray[i] = newarray[i-1] + myarray[i];

}

 

 
Regards,

 

David

 

  _____  

From: amibroker@xxxxxxxxxxxxxxx [mailto:amibroker@xxxxxxxxxxxxxxx] On Behalf
Of NickCivit
Sent: 02/18/2007 7:24 AM
To: amibroker@xxxxxxxxxxxxxxx
Subject: [amibroker] Re: Running total array help

 

--- In amibroker@xxxxxxxxx <mailto:amibroker%40yahoogroups.com> ps.com, "Ara
Kaloustian" <ara1@xxx> wrote:
>Hi Ara, this worked great but I had left out a part that the loop did
not address. I have some zero values in array. So it looks like this:

MyArray = (30,40,-20,0,0,-10);
The results I would like are:
Results = (30,70,50,50,50,40);

The Results I'm getting are 
Results = (30,70,50,-20,0,-10);

Would be greatful if you have a solution.

Nick C.
> have to do it in a loop
> 
> for (i=1; i<=Lastvalue(Barindex()); i++)
> {
> newarray[i] = myarray[i] + myarray[i-1];
> }
> 
> ----- Original Message ----- 
> From: "NickCivit" <nickcivit@xxx>
> To: <amibroker@xxxxxxxxx <mailto:amibroker%40yahoogroups.com> ps.com>
> Sent: Friday, February 16, 2007 8:30 AM
> Subject: [amibroker] Running total array help
> 
> 
> > Hi, I am new to programing and would like to create a running
total of 
> > some numbers in an array. Example:
> > 
> > MyArray = (30,40,-20,-10);
> > Result =(30,70,50,40);
> > 
> > AddColumn(Result,"Result ");
> > 
> > Would appreciate any help,
> > 
> > Nick C.
> > 
> > 
> > 
> > Please note that this group is for discussion between users only.
> > 
> > To get support from AmiBroker please send an e-mail directly to 
> > SUPPORT {at} amibroker.com
> > 
> > For NEW RELEASE ANNOUNCEMENTS and other news always check DEVLOG:
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> > 
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r.com/support.html
> > 
> > Yahoo! Groups Links
> > 
> > 
> >
>

 


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