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Nick,
The following logic should work:
newarray[0] = myarray[0];
for (i=1; i<BarCount; i++)
{
newarray[i] = newarray[i-1] + myarray[i];
}
Regards,
David
_____
From: amibroker@xxxxxxxxxxxxxxx [mailto:amibroker@xxxxxxxxxxxxxxx] On Behalf
Of NickCivit
Sent: 02/18/2007 7:24 AM
To: amibroker@xxxxxxxxxxxxxxx
Subject: [amibroker] Re: Running total array help
--- In amibroker@xxxxxxxxx <mailto:amibroker%40yahoogroups.com> ps.com, "Ara
Kaloustian" <ara1@xxx> wrote:
>Hi Ara, this worked great but I had left out a part that the loop did
not address. I have some zero values in array. So it looks like this:
MyArray = (30,40,-20,0,0,-10);
The results I would like are:
Results = (30,70,50,50,50,40);
The Results I'm getting are
Results = (30,70,50,-20,0,-10);
Would be greatful if you have a solution.
Nick C.
> have to do it in a loop
>
> for (i=1; i<=Lastvalue(Barindex()); i++)
> {
> newarray[i] = myarray[i] + myarray[i-1];
> }
>
> ----- Original Message -----
> From: "NickCivit" <nickcivit@xxx>
> To: <amibroker@xxxxxxxxx <mailto:amibroker%40yahoogroups.com> ps.com>
> Sent: Friday, February 16, 2007 8:30 AM
> Subject: [amibroker] Running total array help
>
>
> > Hi, I am new to programing and would like to create a running
total of
> > some numbers in an array. Example:
> >
> > MyArray = (30,40,-20,-10);
> > Result =(30,70,50,40);
> >
> > AddColumn(Result,"Result ");
> >
> > Would appreciate any help,
> >
> > Nick C.
> >
> >
> >
> > Please note that this group is for discussion between users only.
> >
> > To get support from AmiBroker please send an e-mail directly to
> > SUPPORT {at} amibroker.com
> >
> > For NEW RELEASE ANNOUNCEMENTS and other news always check DEVLOG:
> > http://www.amibroke <http://www.amibroker.com/devlog/> r.com/devlog/
> >
> > For other support material please check also:
> > http://www.amibroke <http://www.amibroker.com/support.html>
r.com/support.html
> >
> > Yahoo! Groups Links
> >
> >
> >
>
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