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Re: [amibroker] puzzled by procedure



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Thanks Terry!

You'd think I'd know that by now, wouldn't you? 
 
 
----- Original Message -----
From: Terry
Sent: Tuesday, May 23, 2006 6:19 PM
Subject: RE: [amibroker] puzzled by procedure

Because there is no such thing as a string array. When it's true (the correct or "true" bar is selected) all occurrences are true and when it's false everything is false.

--

Terry

-----Original Message-----
From:
amibroker@xxxxxxxxxxxxxxx [mailto:amibroker@xxxxxxxxxxxxxxx] On Behalf Of cstrader232
Sent: Tuesday, May 23, 2006 14:37
To:
amibroker@xxxxxxxxxxxxxxx
Subject: Re: [amibroker] puzzled by procedure

 

Hi Ara:

 

Hmmm... 

 

as far as I can tell, FA() should and does return TRUE on and only on the bar where foo==33;  That operates as I expect.

 

It's FB() that I don't get, because it does not return TRUE only on the bar where foo == 33, but, when the 33 bar is selected, it returns TRUE for every bar in the array.

 

As I think about it it must be that FA() is numeric while FB() is array-based.  But how can I get FB() to return an array in which only foo(barcount-10) is true?

 

Sorry to be a pain!

 

 

 

 

----- Original Message -----

Sent: Tuesday, May 23, 2006 4:22 PM

Subject: Re: [amibroker] puzzled by procedure

 

foo ==33 is not a correct structure.

 

== is used as an equality test. Not an assignment of value.

----- Original Message -----

From: cstrader232

Sent: Tuesday, May 23, 2006 1:16 PM

Subject: [amibroker] puzzled by procedure

 

Could someone explain to me why these two function don't work the same way? 

 

Thanks in advance!!

 

foo[BarCount-10] = 33;

procedure FA() {return foo ==33;}

procedure FB() {return StrFind(NumToStr(foo), "3");}

 




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