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Grahm,
Your method will also return cond for not consec seq; 1 1 0 1 0
will be >=3 but not consec...
Walt
--- In amibroker@xxxxxxxxxxxxxxx, Graham <kavemanperth@xxxx> wrote:
> correct it should have been ==3 as there were only 3 bars
considered,
> but the result would have been the same.
>
> You can use (I do)
> Cond = sum(H>ref(H,-1), 5) >=3;
>
>
> On Wed, 16 Mar 2005 23:13:58 -0000, ami_trader <ami_trader@xxxx>
wrote:
> >
> >
> > --- In amibroker@xxxxxxxxxxxxxxx, Graham <kavemanperth@xxxx>
wrote:
> > > you might find similarity to some of the responses above
> > >
> > > cond = sum(H>ref(h,-1),3)==3; // 3 consecutive higher highs
> >
> > Thanks Graham but I need >=3 not ==. I think sum function doesn't
> > permit >=3.
> >
> > ---
> > Giuseppe
> >
> >
> > Please note that this group is for discussion between users only.
> >
> > To get support from AmiBroker please send an e-mail directly to
> > SUPPORT {at} amibroker.com
> >
> > For other support material please check also:
> > http://www.amibroker.com/support.html
> >
> >
> > Yahoo! Groups Links
> >
> >
> >
> >
> >
>
>
> --
> Cheers
> Graham
> http://e-wire.net.au/~eb_kavan/
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