[amibroker] Re: 3 or more consecutive High

["ami_trader" <ami_trader@xxxxxxxxx>]

> correct it should have been ==3 as there were only 3 bars 
considered,
> but the result would have been the same.
> 
> You can use (I do)
> Cond = sum(H>ref(H,-1), 5) >=3;

Graham
1. with this script if I have 5 bar with 3 (or more) NO consecutive 
High it return true and it isn't correct for me.

2. with SUM function I'm limited to the fixed number (5 in this 
scenario) In fact if I have 7 consecutive Hight it doesn't work 
because he count the fixed period (5).

I hope my explanation is good because my english is poor.

---
Giuseppe 





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