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Hi CS,
That *is* a reduction in complexity, <lol>. Thanks.
Yuki
Monday, August 25, 2003, 6:03:08 AM, you wrote:
C> Yuki,
C> FibCMO may also be reduced in complexity from:
C> FibCMO=
C> (100*((Sum(IIf(C>Ref(C,-1),(C-Ref(C,-1)),0),3))-(Sum(IIf(C<Ref(C,-1),(Ref(C,
C> -1)-C),0),3)))/((Sum(IIf(C>Ref(C,-1),(C-Ref(C,-1)),0),3)+(Sum(IIf(C<Ref(C,-1
C> ),(Ref(C,-1)-C),0),3))))+
C> 100*((Sum(IIf(C>Ref(C,-1),(C-Ref(C,-1)),0),5))-(Sum(IIf(C<Ref(C,-1),(Ref(C,-
C> 1)-C),0),5)))/((Sum(IIf(C>Ref(C,-1),(C-Ref(C,-1)),0),5)+(Sum(IIf(C<Ref(C,-1)
C> ,(Ref(C,-1)-C),0),5))))+
C> 100*((Sum(IIf(C>Ref(C,-1),(C-Ref(C,-1)),0),8))-(Sum(IIf(C<Ref(C,-1),(Ref(C,-
C> 1)-C),0),8)))/((Sum(IIf(C>Ref(C,-1),(C-Ref(C,-1)),0),8)+(Sum(IIf(C<Ref(C,-1)
C> ,(Ref(C,-1)-C),0),8)))))/3;
C> To:
C> FibCMO=(100*(C-Ref(C,-3))/Sum(abs(C- Ref(C,-1)),3)+
C> 100*(C-Ref(C,-5))/Sum(abs(C- Ref(C,-1)),5)+
C> 100*(C-Ref(C,-8))/Sum(abs(C- Ref(C,-1)),8))/3;
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