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Anthony: I suppose you could interpolate algebraically from the values
the day after the cross and the day before the cross. What would you do
with the value?
Ken
-----Original Message-----
From: Anthony Faragasso [mailto:ajf1111@xxxxxxxx]
Sent: Thursday, April 03, 2003 3:48 PM
To: amibroker@xxxxxxxxxxxxxxx
Subject: Re: [amibroker] Re: finding the value of a cross condition
Thank you Dimitri....I was just going to post the following:
I was debugging in AA and came up with the following solution;
AddColumn(ValueWhen(Cross(fast,slow),fast),"");
AddColumn(ValueWhen(Cross(fast,slow),slow),"");
My next question was going to be....is it possible to find the value of
the
exact cross value...I assume not....so I must decide to use either the
fast
or slow value......
Again, thank you ....BTW...did you receive my post today.......is it
helpful
? I have another Idea.....
Anthony
-------Original Message-------
From: amibroker@xxxxxxxxxxxxxxx
Date: Thursday, April 03, 2003 15:40:54
To: amibroker@xxxxxxxxxxxxxxx
Subject: [amibroker] Re: finding the value of a cross condition
Anthony ,
In AA
fast=EMA(C,10);
slow=EMA(C,20); cond=Cross(fast,slow);
Filter=Cond;
AddColumn(fast,"fast");
AddColumn(slow,"slow");
or, in IB
fast=EMA(C,10);
slow=EMA(C,20);
Plot(fast,"",1,1);
Plot(slow,"",9,1);
Plot(Cross(fast,slow)*fast,"",5,2);
Plot(Cross(fast,slow)*slow,"",4,8);
Remember that Cross(fast,slow) is binary, 1 or 0.
Note also that you read the values AFTER the cross. [If you want
values BEFORE the cross, use Ref() function]
DT
--- In amibroker@xxxxxxxxxxxxxxx, "Anthony Faragasso" <ajf1111@xxxx>
wrote:
> How can I find the value of a cross condition. I do not what the H,
l, C, or
> Open...but the value when the 2 lines cross....is it possible...
>
> example:
>
> fast=ema(c,10);
> slow=ema(c,20);
>
> cond=cross(fast,slow);
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