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<SPAN
class=252253419-31102002>DT,
does
not
<SPAN
class=252253419-31102002>
<SPAN
class=252253419-31102002>MinRetracement = 6/C * 100 ; PeakValue =
Peak(H,1.2,1) ;Peak(peakvalue,LastValue(MinRetracement),1)
<SPAN
class=252253419-31102002>
solve
the restriction?
Jayson
<FONT face=Tahoma
size=2>-----Original Message-----From: DIMITRIS TSOKAKIS
[mailto:TSOKAKIS@xxxx]Sent: Thursday, October 31, 2002 2:24
PMTo: amibroker@xxxxxxxxxxxxxxxSubject: [amibroker] Re:
peak - trough with variableEsteban,You know better.
Anyway, peak and related functions do not accept variable percentage for
the moment.DT--- In amibroker@xxxx, "Esteban" <ygroups@xxxx>
wrote:> Dimitris,> > I've always looked at percentagesas
you suggest, but when it comes to the eminis basing indicators on points has
kept my methods closer to form than percentage values. The intraday
volatility in points is closer to what it was a year ago than it is in
percentage. A point is still 20 or 50 dollars depending on contract, and the
intraday point movement hasn't changed much.> >
Esteban> > ----- Original Message ----- > From:
DIMITRIS TSOKAKIS > To: amibroker@xxxx >
Sent: Thursday, October 31, 2002 1:50 AM> Subject:
[amibroker] Re: peak - trough with variable> >
> Any formula including Zig, Peak, Trough and related
functions has > only historical value, since it can not be
used in real trading > conditions [looks into the
future].> I wonder for the value of a 6/C*100 when the recent
C is 10 and it > was 40 six months ago. In real trading
we always live with the local > percentage, we want to
take a +5% profit, no matter of absolute >
values.> During a bullish day we will have this +5% for 1$
and [equally] for 50> $ or 100$ stocks or 1000
indices.> I do not see any sense in a C-functional
percentage. On the other > side I suppose peak() does not
accept variable percentage.> Just some thoughts for your
[interesting] question.> DT > --- In
amibroker@xxxx, "Jayson" <jcasavant@xxxx> wrote:> >
> > Esteban,> > >
> > > I'm wanting to find the last peak based on a
fixed number of > points, rather> >
than percentage. So I set a variable to the fixed points value I
> want> > divided by the high * 100 to
give me a percentage to use in the peak> > formula.
But I get an error. Maybe the function needs a value not
> subject> > to fluctuation for
its underlying calculations. Is there a way I > can
use> > this function with a fixed number of
points?> > > > MinRetracement = 6/C
* 100 ; This gives a value of 1.2 percent when > C
=500.> > > > PeakValue =
Peak(H,1.2,1) ; This finds the peaks like I want, when >
price is> > in the range of 500.> >
> > PeakValue Peak(H,MinRetracement,1) ; Gives an
error.> > > > you want the peakof
peakvalue. since peakvalue is a high you > should ask
for> > peak(peakvalue...... your change settingmust
be constant so ask > for the> >
lastvalue of minretracement....> > >
> try......> > > > MinRetracement
= 6/C * 100 ;> > > > PeakValue =
Peak(H,1.2,1) ;> > > >
Peak(peakvalue,LastValue(MinRetracement),1) ;> >
> > jayson> >
> > > > >
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