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Jayson,
I read your proposal yesterday.
The code is correct and works.
But you are restricted to apply the Lastvalue(MinRetracement) to the
whole stock history and I wonder if it is useful.
Esteban knows better his specific needs.
My compliments for your AFL efforts.
DT
--- In amibroker@xxxx, "Jayson" <jcasavant@xxxx> wrote:
> DT,
> does not
>
> MinRetracement = 6/C * 100 ;
> PeakValue = Peak(H,1.2,1) ;
> Peak(peakvalue,LastValue(MinRetracement),1)
>
> solve the restriction?
> Jayson
>
> -----Original Message-----
> From: DIMITRIS TSOKAKIS [mailto:TSOKAKIS@x...]
> Sent: Thursday, October 31, 2002 2:24 PM
> To: amibroker@xxxx
> Subject: [amibroker] Re: peak - trough with variable
>
>
> Esteban,
> You know better.
> Anyway, peak and related functions do not accept variable percentage
> for the moment.
> DT
> --- In amibroker@xxxx, "Esteban" <ygroups@xxxx> wrote:
> > Dimitris,
> >
> > I've always looked at percentages as you suggest, but when it
comes
> to the eminis basing indicators on points has kept my methods closer
> to form than percentage values. The intraday volatility in points is
> closer to what it was a year ago than it is in percentage. A point
is
> still 20 or 50 dollars depending on contract, and the intraday point
> movement hasn't changed much.
> >
> > Esteban
> >
> > ----- Original Message -----
> > From: DIMITRIS TSOKAKIS
> > To: amibroker@xxxx
> > Sent: Thursday, October 31, 2002 1:50 AM
> > Subject: [amibroker] Re: peak - trough with variable
> >
> >
> > Any formula including Zig, Peak, Trough and related functions
has
> > only historical value, since it can not be used in real trading
> > conditions [looks into the future].
> > I wonder for the value of a 6/C*100 when the recent C is 10 and
> it
> > was 40 six months ago. In real trading we always live with the
> local
> > percentage, we want to take a +5% profit, no matter of absolute
> > values.
> > During a bullish day we will have this +5% for 1$ and [equally]
> for 50
> > $ or 100$ stocks or 1000 indices.
> > I do not see any sense in a C-functional percentage. On the
other
> > side I suppose peak() does not accept variable percentage.
> > Just some thoughts for your [interesting] question.
> > DT
> > --- In amibroker@xxxx, "Jayson" <jcasavant@xxxx> wrote:
> > >
> > > Esteban,
> > >
> > >
> > > I'm wanting to find the last peak based on a fixed number of
> > points, rather
> > > than percentage. So I set a variable to the fixed points value
> I
> > want
> > > divided by the high * 100 to give me a percentage to use in
the
> peak
> > > formula. But I get an error. Maybe the function needs a value
> not
> > subject
> > > to fluctuation for its underlying calculations. Is there a
way
> I
> > can use
> > > this function with a fixed number of points?
> > >
> > > MinRetracement = 6/C * 100 ; This gives a value of 1.2 percent
> when
> > C =500.
> > >
> > > PeakValue = Peak(H,1.2,1) ; This finds the peaks like I want,
> when
> > price is
> > > in the range of 500.
> > >
> > > PeakValue Peak(H,MinRetracement,1) ; Gives an error.
> > >
> > > you want the peak of peakvalue. since peakvalue is a high you
> > should ask for
> > > peak(peakvalue...... your change setting must be constant so
> ask
> > for the
> > > lastvalue of minretracement....
> > >
> > > try......
> > >
> > > MinRetracement = 6/C * 100 ;
> > >
> > > PeakValue = Peak(H,1.2,1) ;
> > >
> > > Peak(peakvalue,LastValue(MinRetracement),1) ;
> > >
> > > jayson
> > >
> > >
> > >
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