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Esteban,
You know better.
Anyway, peak and related functions do not accept variable percentage
for the moment.
DT
--- In amibroker@xxxx, "Esteban" <ygroups@xxxx> wrote:
> Dimitris,
>
> I've always looked at percentages as you suggest, but when it comes
to the eminis basing indicators on points has kept my methods closer
to form than percentage values. The intraday volatility in points is
closer to what it was a year ago than it is in percentage. A point is
still 20 or 50 dollars depending on contract, and the intraday point
movement hasn't changed much.
>
> Esteban
>
> ----- Original Message -----
> From: DIMITRIS TSOKAKIS
> To: amibroker@xxxx
> Sent: Thursday, October 31, 2002 1:50 AM
> Subject: [amibroker] Re: peak - trough with variable
>
>
> Any formula including Zig, Peak, Trough and related functions has
> only historical value, since it can not be used in real trading
> conditions [looks into the future].
> I wonder for the value of a 6/C*100 when the recent C is 10 and
it
> was 40 six months ago. In real trading we always live with the
local
> percentage, we want to take a +5% profit, no matter of absolute
> values.
> During a bullish day we will have this +5% for 1$ and [equally]
for 50
> $ or 100$ stocks or 1000 indices.
> I do not see any sense in a C-functional percentage. On the other
> side I suppose peak() does not accept variable percentage.
> Just some thoughts for your [interesting] question.
> DT
> --- In amibroker@xxxx, "Jayson" <jcasavant@xxxx> wrote:
> >
> > Esteban,
> >
> >
> > I'm wanting to find the last peak based on a fixed number of
> points, rather
> > than percentage. So I set a variable to the fixed points value
I
> want
> > divided by the high * 100 to give me a percentage to use in the
peak
> > formula. But I get an error. Maybe the function needs a value
not
> subject
> > to fluctuation for its underlying calculations. Is there a way
I
> can use
> > this function with a fixed number of points?
> >
> > MinRetracement = 6/C * 100 ; This gives a value of 1.2 percent
when
> C =500.
> >
> > PeakValue = Peak(H,1.2,1) ; This finds the peaks like I want,
when
> price is
> > in the range of 500.
> >
> > PeakValue Peak(H,MinRetracement,1) ; Gives an error.
> >
> > you want the peak of peakvalue. since peakvalue is a high you
> should ask for
> > peak(peakvalue...... your change setting must be constant so
ask
> for the
> > lastvalue of minretracement....
> >
> > try......
> >
> > MinRetracement = 6/C * 100 ;
> >
> > PeakValue = Peak(H,1.2,1) ;
> >
> > Peak(peakvalue,LastValue(MinRetracement),1) ;
> >
> > jayson
> >
> >
> >
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