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Steve,
as for the quantitative explanation you may see
http://groups.yahoo.com/group/amibroker/message/25614
I try to see a qualitative reason and some realistic interpretation
[and of course some possible use]
Note also that this RSI*RSI/100 is below 25 in both RSI>50 or RSI<50
cases.
DT
--- In amibroker@xxxx, "Steve Dugas" <sjdugas@xxxx> wrote:
> Hi DT,
>
> This got me hooked, so I had to get out the pencil and paper. It
seems that
> they are only equal when RSI(t) = 50. I dont think the stock
matters, or
> even the number of periods - since RSI(t) is still RSI(t) on both
sides of
> the equation, we could just replace it with x. Picking a few
values, I came
> up with the following chart:
>
> x (RSIt) x*x/100 x-25 difference
> ----------- ----------- ------ --------------
> 0 0 -25 25
> 10 1 -15 16
> 20 4 -5 9
> 30 9 5 4
> 40 16 15 1
> 50 25 25 0
> 60 36 35 1
> 70 49 45 4
> 80 64 55 9
> 90 81 65 16
> 100 100 75 25
>
>
> So we can see the difference continues to get symetrically larger
the
> further away from the center that we get. It is interesting that the
> difference is always a square - I suppose as a result of the initial
> squaring of x.
>
> I guess I will go out now and try to find a life... : - )
>
>
> Steve
>
>
> ----- Original Message -----
> From: "DIMITRIS TSOKAKIS" <TSOKAKIS@xxxx>
> To: <amibroker@xxxx>
> Sent: Wednesday, October 02, 2002 3:15 PM
> Subject: [amibroker] RSI relations
>
>
> > Does anybody can give a qualitative explanation why
> > RSI(t)*RSI(t)/100 is mostly equal to RSI(t)-25 for any t and for
any
> > stock ?
> > Dimitris Tsokakis
> >
> >
> >
> > Post AmiQuote-related messages ONLY to: amiquote@xxxx
> > (Web page: http://groups.yahoo.com/group/amiquote/messages/)
> >
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> >
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http://docs.yahoo.com/info/terms/
> >
> >
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