|
PureBytes Links
Trading Reference Links
|
Hi DT,
This got me hooked, so I had to get out the pencil and paper. It seems that
they are only equal when RSI(t) = 50. I dont think the stock matters, or
even the number of periods - since RSI(t) is still RSI(t) on both sides of
the equation, we could just replace it with x. Picking a few values, I came
up with the following chart:
x (RSIt) x*x/100 x-25 difference
----------- ----------- ------ --------------
0 0 -25 25
10 1 -15 16
20 4 -5 9
30 9 5 4
40 16 15 1
50 25 25 0
60 36 35 1
70 49 45 4
80 64 55 9
90 81 65 16
100 100 75 25
So we can see the difference continues to get symetrically larger the
further away from the center that we get. It is interesting that the
difference is always a square - I suppose as a result of the initial
squaring of x.
I guess I will go out now and try to find a life... : - )
Steve
----- Original Message -----
From: "DIMITRIS TSOKAKIS" <TSOKAKIS@xxxx>
To: <amibroker@xxxxxxxxxxxxxxx>
Sent: Wednesday, October 02, 2002 3:15 PM
Subject: [amibroker] RSI relations
> Does anybody can give a qualitative explanation why
> RSI(t)*RSI(t)/100 is mostly equal to RSI(t)-25 for any t and for any
> stock ?
> Dimitris Tsokakis
>
>
>
> Post AmiQuote-related messages ONLY to: amiquote@xxxxxxxxxxxxxxx
> (Web page: http://groups.yahoo.com/group/amiquote/messages/)
>
> Check group FAQ at:
http://groups.yahoo.com/group/amibroker/files/groupfaq.html
>
> Your use of Yahoo! Groups is subject to http://docs.yahoo.com/info/terms/
>
>
|