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Frank,
>>>i have these 5 datastreams
>>>data2 , data3 , data4 , data5 , data6
>bingo
Well, OK, all he needs to do is change the starting value of the
loop to 2 instead of 1. And N=6, the index of the last data stream.
>>>and i want every possible combination of [up to 3 of] these
>
>AM> That's simple IF you want only every permutation of three of them.
>AM> You just have a triple nested loop like so:
>
>AM> ---------------------------------------------------------------------
>AM> vars: N(0), d1(0), d2(0), d3(0);
>AM> {N = number of data streams (data1 ... dataN)}
>
>AM> for d1 = 1 to N-2 begin
>AM> for d2 = d1+1 to N-1 begin
>AM> for d3 = d2+1 to N begin
>
>AM> {your code goes here, and you reference the three
>AM> data streams as data(d1), data(d2) and data(d3),
>AM> instead of explicityly referencing data3, data7, etc.}
>
>AM> end;
>AM> end;
>AM> end;
>AM> ---------------------------------------------------------------------
>
>AM> However, if you want to get single and pair combos as well as triple
>AM> combos, you need to change the loop bounds to allow for duplicates,
>AM> and then make comparisons to check when 2 or more are duplicated,
>AM> and have separate code sections to handle singles, pairs of values,
>AM> and three values. Like this:
>
>AM> ---------------------------------------------------------------------
>
>AM> for d1 = 1 to N begin
>AM> for d2 = d1 to N begin
>AM> for d3 = d2 to N begin
>
>AM> if d1=d2 AND d2=d3 then begin
>AM> {code for single value goes here, just use data(d1)}
>AM> end
>
>AM> else if d1=d2 OR d2=d3
>AM> {code for pair combos goes here; use data(d1) and data(d3)
>AM> as your data streams}
>AM> end
>
>AM> else
>AM> {code for triple combos goes here; use
>AM> data(d1), data(d2) and data(d3)}
>AM> end;
>
>AM> end;
>AM> end;
>AM> end;
>AM> ---------------------------------------------------------------------
--
,|___ Alex Matulich -- alex@xxxxxxxxxxxxxx
// +__> Director of Research and Development
// \
// __) Unicorn Research Corporation -- http://unicorn.us.com
|