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Rk,
this is not correct.
What the above thing is telling us (and you're quite right on this) is that when both conditions are met then we have 1 while before we have 0 and that's what the .5 crossover is all about. But if you read carefully, we do not have crossovers, thus what we really want to happen is simply both pdi>mdi and c>sma which does not mean that the crossovers are happening the very same day at least not necessarily. One may happen first and the buy signal waits for the other condition to turn true and then it turns on.
Perhaps a more clear way to write this, might be:
a:=pdi(14)>mdi(14) and c>mov(c,30,s);
a>ref(a,-1)
Regards,
mc
--- In equismetastock@xxxxxxxxxxxxxxx, "rk" <rk1235_mb@xxx> wrote:
>
> Cross(c1 AND c2,0.5) means ,when both the events i.e. c1 and c2 (value 1)
> cross 0.5, i.e. happen together............
>
> means- when pdi crosses mdi AND c crosses mov30 together on the same
> day.........
>
> does not appear to be a good system, as the probability of both crossing on
> the same day is very less and one is likely to miss many good
> moves...........
>
> rk
>
> ----- Original Message -----
> From: "pumrysh" <no_reply@xxxxxxxxxxxxxxx>
> To: <equismetastock@xxxxxxxxxxxxxxx>
> Sent: Friday, August 14, 2009 8:44 AM
> Subject: [EquisMetaStock Group] Re: How can I interpret cross function ?
>
> Carlos,
>
> This is from the help files.
>
> SYNTAX cross( DATA ARRAY 1, DATA ARRAY 2 )
>
> FUNCTION Plots a "+1" on the day that DATA ARRAY 1 crosses above DATA ARRAY
> 2. Otherwise, "0" is plotted.
>
> If you want to know when DATA ARRAY 1 crosses below DATA ARRAY 2, use the
> formula "cross( DATA ARRAY 2, DATA ARRAY 1)"
>
> EXAMPLE cross( close, mov(close,9,e) )
>
>
> In your example the c1 variable would yield a value of 1 when the PDI(14)was
> greater than >MDI(14). The c2 variable would yield a value of 1 when the
> close is greater than its 30 day simple moving average.
>
> Sorry but I do not follow the Cross argument.
>
>
> Preston
>
> --- In equismetastock@xxxxxxxxxxxxxxx, "carlosarturosierra"
> <carlosarturosierra@> wrote:
> >
> > Hello Group,
> >
> > I saw the following system tester in a magazine:
> >
> > Buy Order
> >
> > c1:=PDI(14)>MDI(14);
> > c2:=C>Mov(C,30,S);
> > Cross(c1 AND c2,0.5)
> >
> > Could you please help me to interpret in a correct way the Cross function
> > in the previous example. I do not understand the parameter 0.5 in the c2
> > variable.
> >
> > I really appreciate your help
> >
> > Sincerely,
> >
> > Carlos Sierra
> >
>
>
>
>
> ------------------------------------
>
> Yahoo! Groups Links
>
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