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Cross(c1 AND c2,0.5) means ,when both the events i.e. c1 and c2 (value 1)
cross 0.5, i.e. happen together............
means- when pdi crosses mdi AND c crosses mov30 together on the same
day.........
does not appear to be a good system, as the probability of both crossing on
the same day is very less and one is likely to miss many good
moves...........
rk
----- Original Message -----
From: "pumrysh" <no_reply@xxxxxxxxxxxxxxx>
To: <equismetastock@xxxxxxxxxxxxxxx>
Sent: Friday, August 14, 2009 8:44 AM
Subject: [EquisMetaStock Group] Re: How can I interpret cross function ?
Carlos,
This is from the help files.
SYNTAX cross( DATA ARRAY 1, DATA ARRAY 2 )
FUNCTION Plots a "+1" on the day that DATA ARRAY 1 crosses above DATA ARRAY
2. Otherwise, "0" is plotted.
If you want to know when DATA ARRAY 1 crosses below DATA ARRAY 2, use the
formula "cross( DATA ARRAY 2, DATA ARRAY 1)"
EXAMPLE cross( close, mov(close,9,e) )
In your example the c1 variable would yield a value of 1 when the PDI(14)was
greater than >MDI(14). The c2 variable would yield a value of 1 when the
close is greater than its 30 day simple moving average.
Sorry but I do not follow the Cross argument.
Preston
--- In equismetastock@xxxxxxxxxxxxxxx, "carlosarturosierra"
<carlosarturosierra@xxx> wrote:
>
> Hello Group,
>
> I saw the following system tester in a magazine:
>
> Buy Order
>
> c1:=PDI(14)>MDI(14);
> c2:=C>Mov(C,30,S);
> Cross(c1 AND c2,0.5)
>
> Could you please help me to interpret in a correct way the Cross function
> in the previous example. I do not understand the parameter 0.5 in the c2
> variable.
>
> I really appreciate your help
>
> Sincerely,
>
> Carlos Sierra
>
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