|
PureBytes Links
Trading Reference Links
|
hi lionel,
thanks for the clarification and information. have taken a note of the same.
though i am not a maths expert and had writen to try it practically. thanks
for the exact answer.
but could not understand what you mean by saying
"In this situation, the "angle" in degrees is meaningless as price and time
are different measures, and the "angle" would depend on the scales used for
price and time."
the motive is to filter securities which are rising with the highest roc
angle. whether the same be applied to the intraday,daily or weekly charts.
it would give the same result. i.e filter the stocks having steepest moving
average.
comments appreciated.
regards
joshik
On 1/14/07, Lionel Issen <lissen@xxxxxxxxxxxxx> wrote:
>
> OOP
> OOPS! my error.
>
> A rate of change of 50% is equivalent to an angle of 26 degrees 34
> minutes.
>
> _____
>
> From: Lionel Issen [mailto:lissen@xxxxxxxxxxxxx <lissen%40sbcglobal.net>]
> Sent: Saturday, January 13, 2007 9:25 AM
> To: 'equismetastock@xxxxxxxxxxxxxxx <%27equismetastock%40yahoogroups.com>'
> Subject: RE: [EquisMetaStock Group] formula help Mov() angle
>
> Joshik:
>
> The rate of change is the tangent of the "angle". Hence an ROC of 100% is
> equivalent to an "angle" of 45 degrees, and a rate of change of 50% is
> equivalent to an "angle" of 30 degrees: just look up a table of tangents
> in
> a mathematics book.
>
> In this situation, the "angle" in degrees is meaningless as price and time
> are different measures, and the "angle" would depend on the scales used
> for
> price and time.
>
> I agree with the rest of your posting.
>
> Hope this helps
>
> Lionel
>
> _____
>
> From: equismetastock@xxxxxxxxxxxxxxx <equismetastock%40yahoogroups.com>[mailto:
> equismetastock@xxxxxxxxxxxxxxx <equismetastock%40yahoogroups.com>]
> On Behalf Of stock market
> Sent: Saturday, January 13, 2007 12:06 AM
> To: equismetastock@xxxxxxxxxxxxxxx <equismetastock%40yahoogroups.com>
> Subject: Re: [EquisMetaStock Group] formula help Mov() angle
>
> hi, phillip,
>
> you can find the Rate of change of the moving average. and then this rate
> of
> change would give you the angle at which the moving average is.
>
> ROC(mov(c,35,E),1,%)
>
> Use a higher ROC period to find the angle of more days. the above gives
> the
> angle of 1 day. MOV is a curve so it would give diff. angles for different
> days at any given point.
>
> i think that if the ROC is 100% then the angle would be 90 degree and if
> the
> ROC is 50% then angle should be 45 degree. try it practically and you can
> get the solution.
> joshik
>
> On 1/13/07, pennellp2000 <no_reply@xxxxxxxxxx
> <mailto:no_reply% <no_reply%25>40yahoogroups.com> s.com> wrote:
> >
> > Is there any way to put the angle of a moving average line in a
> > formula, eg Mov(35) has been rising at 45 degrees for 20 periods.
> >
> > Thanks in advance Phillip
> >
> >
> >
>
> [Non-text portions of this message have been removed]
>
> [Non-text portions of this message have been removed]
>
>
>
[Non-text portions of this message have been removed]
Yahoo! Groups Links
<*> To visit your group on the web, go to:
http://groups.yahoo.com/group/equismetastock/
<*> Your email settings:
Individual Email | Traditional
<*> To change settings online go to:
http://groups.yahoo.com/group/equismetastock/join
(Yahoo! ID required)
<*> To change settings via email:
mailto:equismetastock-digest@xxxxxxxxxxxxxxx
mailto:equismetastock-fullfeatured@xxxxxxxxxxxxxxx
<*> To unsubscribe from this group, send an email to:
equismetastock-unsubscribe@xxxxxxxxxxxxxxx
<*> Your use of Yahoo! Groups is subject to:
http://docs.yahoo.com/info/terms/
|