[EquisMetaStock Group] formula help Mov() angle

["Lionel Issen" <lissen@xxxxxxxxxxxxx>]

OOP
OOPS! my error.
 
A rate of change of 50% is equivalent to an angle of 26 degrees 34 minutes. 

  _____  

From: Lionel Issen [mailto:lissen@xxxxxxxxxxxxx] 
Sent: Saturday, January 13, 2007 9:25 AM
To: 'equismetastock@xxxxxxxxxxxxxxx'
Subject: RE: [EquisMetaStock Group] formula help Mov() angle


Joshik:
 
The rate of change is the tangent of the "angle". Hence an ROC of 100% is
equivalent to an "angle" of 45 degrees, and a rate of change of 50% is
equivalent to an "angle" of 30 degrees: just look up a table of tangents in
a mathematics book.
 
In this situation, the "angle" in degrees is meaningless as price and time
are different measures, and the "angle" would depend on the scales used for
price and time.
 
I agree with the rest of your posting.
 
Hope this helps
 
Lionel

  _____  

From: equismetastock@xxxxxxxxxxxxxxx [mailto:equismetastock@xxxxxxxxxxxxxxx]
On Behalf Of stock market
Sent: Saturday, January 13, 2007 12:06 AM
To: equismetastock@xxxxxxxxxxxxxxx
Subject: Re: [EquisMetaStock Group] formula help Mov() angle



hi, phillip,

you can find the Rate of change of the moving average. and then this rate of
change would give you the angle at which the moving average is.

ROC(mov(c,35,E),1,%)

Use a higher ROC period to find the angle of more days. the above gives the
angle of 1 day. MOV is a curve so it would give diff. angles for different
days at any given point.

i think that if the ROC is 100% then the angle would be 90 degree and if the
ROC is 50% then angle should be 45 degree. try it practically and you can
get the solution.
joshik

On 1/13/07, pennellp2000 <no_reply@xxxxxxxxxx
<mailto:no_reply%40yahoogroups.com> s.com> wrote:
>
> Is there any way to put the angle of a moving average line in a
> formula, eg Mov(35) has been rising at 45 degrees for 20 periods.
>
> Thanks in advance Phillip
>
> 
>

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