[EquisMetaStock Group] Re: Need codes for finding the trough of an oscillator

["awlaimeng" <awlaimeng@xxxxxxxxx>]

Hi! Jose,

Thank you for showing me how to program the 4 parameters as user input 
variables and also the tips on using the Sum() funstion. They are just 
awesome!

Best regards,
ALM


--- In equismetastock@xxxxxxxxxxxxxxx, "Jose Silva" <josesilva22@xxxx> 
wrote:
> Alm, you could try adding some user inputs to your indicator, and 
> simplifying some of the code with the Sum() MS function:
> 
> ---8<-------------------------
> 
> { User inputs }
> pds:=Input("Osc trough moving downwards last x periods",1,260,5);
> pr1:=Input("ROC 1, %",0,100,14);
> pr2:=Input("ROC 2, %",0,100,11);
> pds1:=Input("WMA periods",1,260,10);
> 
> { Oscillator }
> CP:=Mov(ROC(C,pr1,%)+ROC(C,pr2,%),pds1,W);
> 
> { Oscillator currently in negative zone }
> CP<0
> 
> { Osc trough }
> { Osc moving upwards on latest bar }
>  AND CP>Ref(CP,-1)
> 
> {... and moving downwards in last x periods }
>  AND Sum(Ref(CP,-1)<Ref(CP,-2),pds)=pds
> 
> ---8<-------------------------
> 
> 
> > {and moving downwards last 6 periods}
> 
> Note that your original code looks for a downward movement in only
> the previous five bars.
> 
> 
> jose '-)
> http://metastocktools.com
> 
> 
> 
> --- In equismetastock@xxxxxxxxxxxxxxx, "awlaimeng" 
> <awlaimeng@xxxx> wrote:
> >
> > I have the following oscillator and would like to know whether
> there 
> > is a better way of finding the "trough" (valley) when the
> > oscillator moves from the negative zone and starts to move 
upwards.
> > 
> > 
> > {oscillator}
> > CP:=Mov(ROC(C,14,%)+ROC(C,11,%),10,W); 
> > 
> > {oscillator below zero line - in negative zone}
> > CP<0 
> > 
> > {finding the trough}
> > {moving upwards on latest period}
> > {and moving downwards last 6 periods}
> > AND CP>Ref(CP,-1) AND 
> > Ref(CP,-1)<Ref(CP,-2) AND
> > Ref(CP,-2)<Ref(CP,-3) AND
> > Ref(CP,-3)<Ref(CP,-4) AND
> > Ref(CP,-4)<Ref(CP,-5) AND
> > Ref(CP,-5)<Ref(CP,-6)
> > 
> > Any comments on the above codes will be much appreciated.
> > 
> > Thank you and best regards,
> > ALM






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