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Hi Jim
Jose Silva gave me that tip for reducing code, it wasn't my own bright idea.
Regards
Roy
>
> Roy,
>
> Oh, okay. That's pretty neat. I had to wrap my head around
> Ref(H-L,-1)>=(H-L) being something other than an integer and all is well.
>
> Thanks,
>
> Jim
>
>
> ----- Original Message -----
> From: "Roy Larsen" <rlarsen@xxxxxxxxxxxxxx>
> To: <Metastockusers@xxxxxxxxxxxxxxx>
> Sent: Tuesday, December 07, 2004 9:06 PM
> Subject: Re: [Metastockusers] Decreasing Range: Best way to code for
>
>
>>
>> Hi Jim
>>
>> > Can you help me understand how this works?
>> >
>> > Sum(Ref(H-L,-1)
>> >
>> > [the sum of yesterday's HI - LOW]
>> >
>> > >=
>> >
>> > [Is greater than or equal to]
>> >
>> > (H-L),3) =3
>> >
>> > [This part I can't parse...]
>>
>> Look at it in a different way.
>>
>> Ref(H-L,-1)>=(H-L) evaluates the current bars range against the previous
> bars range, OK?
>>
>> Now what you want to do is check whether the same expression was was true
> on the on the previous
>> bar, and the bar before that?
>> The expression being TRUE for three contiguous bars in fact.
>>
>> Sum the result of the expression for three bars and check that the answer
> is three.
>>
>> Sum( Ref(H-L,-1)>=(H-L) , 3 {sum expression result for 3 bars } ) =3
> {if expression is true for
>> 3 bars in a row the sum result must be 3}
>>
>> > BTW, your help with the IF function in the Improved OBV worked fine.
>>
>> Was that me?
>>
>> > My skills will get better with a little practice. I'd love to say it's
> all
>> > coming back to me now, but I'd be lying.
>>
>> I know the feeling.
>>
>> Kind regards
>>
>> Roy Larsen
>> www.metastocktips.co.nz
>> Free formulas and MS links
>
>
>
>
>
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