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Roy,
Oh, okay. That's pretty neat. I had to wrap my head around
Ref(H-L,-1)>=(H-L) being something other than an integer and all is well.
Thanks,
Jim
----- Original Message -----
From: "Roy Larsen" <rlarsen@xxxxxxxxxxxxxx>
To: <Metastockusers@xxxxxxxxxxxxxxx>
Sent: Tuesday, December 07, 2004 9:06 PM
Subject: Re: [Metastockusers] Decreasing Range: Best way to code for
>
> Hi Jim
>
> > Can you help me understand how this works?
> >
> > Sum(Ref(H-L,-1)
> >
> > [the sum of yesterday's HI - LOW]
> >
> > >=
> >
> > [Is greater than or equal to]
> >
> > (H-L),3) =3
> >
> > [This part I can't parse...]
>
> Look at it in a different way.
>
> Ref(H-L,-1)>=(H-L) evaluates the current bars range against the previous
bars range, OK?
>
> Now what you want to do is check whether the same expression was was true
on the on the previous
> bar, and the bar before that?
> The expression being TRUE for three contiguous bars in fact.
>
> Sum the result of the expression for three bars and check that the answer
is three.
>
> Sum( Ref(H-L,-1)>=(H-L) , 3 {sum expression result for 3 bars } ) =3
{if expression is true for
> 3 bars in a row the sum result must be 3}
>
> > BTW, your help with the IF function in the Improved OBV worked fine.
>
> Was that me?
>
> > My skills will get better with a little practice. I'd love to say it's
all
> > coming back to me now, but I'd be lying.
>
> I know the feeling.
>
> Kind regards
>
> Roy Larsen
> www.metastocktips.co.nz
> Free formulas and MS links
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