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Ron,
Many thanks for this idea. <span
> Brute force it may be, but it worked for
me!
<span
>Preston<font
size=2 color=navy face=Arial> and <font size=2 color=navy
face=Arial>Roy<font
size=2 color=navy face=Arial>,
Thanks for your ideas,
I only wish I was sufficiently familiar with the MetaStock programming language
to be able to apply them.
Cheers,
Barry
<font size=2
face="Courier New">Barry,<font
size=2 face="Courier New">
I think you can do it by brute force something
like:
C1:=max((max(mov(c,10,s),mov(c,11,s)),(max(mov(c,12,s),mov(c,13,s));
C2:=max((max(mov(c,14,s),mov(c,15,s)),(max(mov(c,16,s),mov(c,17,s));
C3:=max((max(mov(c,18,s),mov(c,19,s)),(max(mov(c,20,s),mov(c,21,s));
C4:=max((max(mov(c,22,s),mov(c,23,s)),(max(mov(c,24,s),mov(c,25,s));
C5:=max((max(mov(c,26,s),mov(c,27,s)),(max(mov(c,28,s),mov(c,29,s));
C6:=max(c1,c2);
C7:=max(C3,c4);
C8:=max(C5,mov(c,30,s));
c9:=max(c6,c7);
c10:=max(c8,c9);
cmax<font
face="Courier New">:=max(c9,c10);
I didn't test it, but I think you can get the
idea.
Ron
pumrysh wrote:
> Barry,
>
> Try using the HHV [highest high value]. Since
you are planning on
> using a variable moving average you may
experience some difficulty.
> It can be done though. Post your code and I'm
sure some of the great
> coders on this site will be able to help you.
>
> <font
size=2 face="Courier New">Preston<font
size=2 face="Courier New">
>
> --- In equismetastock@xxxxxxxxxxxxxxx,
"Barry Seeger"
> <barry.seeger@xxxx> wrote:
> > MetaStock Users,
> >
> > Can anyone tell me how to go about
finding the maximum value of a
> > variable when one parameter is allowed
to vary, and use the
> resulting
> > value of the variable in an indicator
formula? Let's say I want to
> > discover today's maximum value of the
simple moving average of
> closing
> > price, where the averaging period can be
anything from the last 10
> to 30
> > periods. That is, I want to find the
maximum value of mov(c,10,s),
> > mov(c,11,s) etc right through to mov(c,30,s).
Then I'll use the
> > resulting highest moving average value
in a formula, and plot the
> > result.
> >
> > Many thanks for your help,
> > Barry
>
>
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