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Corey
> In all of the instances that I tried,
>
> Cum(sigtl+rsttl>-1)=1;
>
> worked the same as
>
> Cum(sigtl+rsttl)=1;
> Probably luck.
Your example treats the values as binary. They may in fact be zero or any
positive value (price). Using ">-1" as a nominal reference value works fine
but ">0" would not because there's a very good chance that both (three or
more in some formulas) will be zero when the first bar is zero. You may have
forgotten but MS will treat every price under $1 as a binary zero (false),
if the value is presented to it as binary, and every value equal or over $1
as a binary one (true). Therefore my construction works in every case as
long as negative numbers are not used. Other constructions may have
loopholes. I may not have presented a good case here but believe me, my
construction is better (best is still illusive).
Roy
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