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Re: [Metastockusers] RE:Re: Bar Count since certain date



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Lionel,
 
my bad English doesn't help us... :-)
 
Look at rhis site where there are a full description of what you already 
know, I think
<A 
href="http://schools.spsd.sk.ca/mount/Hoffman/MathC30/Parabola/parabola.htm#trinomial";>http://schools.spsd.sk.ca/mount/Hoffman/MathC30/Parabola/parabola.htm#trinomial
 
 
I find this about autocad (I don't use it)
<A 
href="http://xarch.tu-graz.ac.at/autocad/news/lisp_progs/msg00013.html";>http://xarch.tu-graz.ac.at/autocad/news/lisp_progs/msg00013.html
 
and anyway the results of this search say that wee need three points for 
building a parabola (by solving a system of equations I remember - maybe :-) 
)
 
 
<A 
href="http://www.google.it/search?q=build+parabola+three+points&hl=it&lr=&ie=UTF-8&oe=UTF-8&start=0&sa=N";>http://www.google.it/search?q=build+parabola+three+points&hl=it&lr=&ie=UTF-8&oe=UTF-8&start=0&sa=N
 
 
I hope your math knowledge is better than mine and unserstand what I'd like 
to say.
 
 
 
    robin
 
 
 
<BLOCKQUOTE 
style="PADDING-RIGHT: 0px; PADDING-LEFT: 5px; MARGIN-LEFT: 5px; BORDER-LEFT: #000000 2px solid; MARGIN-RIGHT: 0px">
  ----- Original Message ----- 
  <DIV 
  style="BACKGROUND: #e4e4e4; FONT: 10pt arial; font-color: black">From: 
  Lionel 
  Issen 
  To: <A 
  title=Metastockusers@xxxxxxxxxxxxxxx 
  href="mailto:Metastockusers@xxxxxxxxxxxxxxx";>Metastockusers@xxxxxxxxxxxxxxx 
  
  Sent: Sunday, January 05, 2003 3:13 
  PM
  Subject: RE: [Metastockusers] RE:Re: Bar 
  Count since certain date
  
  <FONT face=Arial 
  size=2>Robin:
  <FONT face=Arial 
  size=2> 
  Can you direct me 
  to the portion of the cited web site where it says that 3 points are 
  sufficient to define a parabola? Three points would be sufficient to define a 
  parabola if you know the semi latus rectum (factor F 
  below).
  <FONT face=Arial 
  size=2> 
  Please bear with 
  me. While both the circle and the parabola are conic sections their equations 
  are different.
  <FONT face=Arial 
  size=2> 
  Equation of Circle 
  : X**2 + Y**2 = R**2    R is the radius
  <FONT face=Arial 
  size=2> 
  Equation of 
  parabola: Y**2 = 
  4FX            F is the 
  semi latus rectum
  <FONT face=Arial 
  size=2> 
  Here is a little 
  exercise you can do.  All you need are two pieces of paper, a 
  pencil, a compass, a straight edge (a ruler will do) and maybe an 
  eraser.
   
  Place 3 points on 
  a piece of paper, they must not be on a straight line. Call them A, B, and C. 
  Draw the lines A-B and B-C. Bisect these 2 lines and draw the perpendicular 
  bisectors. the bisectors will meet at the center of the circle. Next select 
  any other 3 points on the circle and repeat this little 
  exercise.  These bisectors will also meet at the center of the 
  circle.  Before the days of electronic navigation, the basis of 
  this method was used by navigators near shore or in narrow 
  channels to locate the position of the vessel.
  <FONT face=Arial 
  size=2> 
  If you draw a 
  parabola and select two or more sets of three points on the parabola 
  and repeat the exercise, the bisectors will not meet at the same 
  place.
  <FONT face=Arial 
  size=2> 
  If you have any 
  further questions please write me privately
  <FONT face=Arial 
  size=2> 
  <FONT face=Arial 
  size=2>Lionel
  <FONT face=Arial 
  size=2> 
  <FONT face=Arial 
  size=2> 
  <FONT face=Arial 
  size=2> 
  
  
  <FONT 
  face=Tahoma size=2>-----Original Message-----From: Robin Hood 
  [mailto:robinhood@xxxxxxxx] Sent: Sunday, January 05, 2003 4:51 
  AMTo: Metastockusers@xxxxxxxxxxxxxxxSubject: Re: 
  [Metastockusers] RE:Re: Bar Count since certain date
  Hi Lionel
   
  Three points are sufficient as parabola is made by tho points 
  equidistanced (? in english ?) form another one.
  <A 
  href="http://www.xahlee.org/SpecialPlaneCurves_dir/Parabola_dir/parabola.html";>http://www.xahlee.org/SpecialPlaneCurves_dir/Parabola_dir/parabola.html for 
  examples (by google).
   
  Here is a chart form an Italian site which I don't name because of 
  netiquette (I think...). They build a parabola from three points, in effect. 
  It's the same effect I'd like to reproduce with Metastock... but the trouble 
  are the input dates (x coordinates) :-(
   
   
   
      robin
   
   
  <BLOCKQUOTE 
  style="PADDING-RIGHT: 0px; PADDING-LEFT: 5px; MARGIN-LEFT: 5px; BORDER-LEFT: #000000 2px solid; MARGIN-RIGHT: 0px">
    ----- Original Message ----- 
    <DIV 
    style="BACKGROUND: #e4e4e4; FONT: 10pt arial; font-color: black">From: 
    Lionel 
    Issen 
    To: <A 
    title=Metastockusers@xxxxxxxxxxxxxxx 
    href="mailto:Metastockusers@xxxxxxxxxxxxxxx";>Metastockusers@xxxxxxxxxxxxxxx 
    
    Sent: Saturday, January 04, 2003 4:57 
    PM
    Subject: RE: [Metastockusers] RE:Re: 
    Bar Count since certain date
    
    Three points 
    always define a circle. I think that you need at least 4 points to 
    define a parabola. When curve fitting a parabola you need more than 4 points 
    as data points always have some noise, they don't fall on a nice smooth 
    curve.
     
     
    
    
    <FONT 
    face=Tahoma size=2>-----Original Message-----From: Robin Hood 
    [mailto:robinhood@xxxxxxxx] Sent: Saturday, January 04, 2003 8:25 
    AMTo: Metastockusers@xxxxxxxxxxxxxxxSubject: Re: 
    [Metastockusers] RE:Re: Bar Count since certain date
    Hi Group
     
    Thanks to Spyros for his formula.
     
     
    In order to build a parabolic trend-line, I need three points (geometry 
    requires it). It means three x,y (date, price) coordinates.
     
    The problem is that metastock accepts only six inputs (in oder to 
    define dates I need 3+3+3=9 inputs :-( ).
     
    Is there another way to make this?
     
    Now, the formula inputs are as follows, but I'd like to change the 
    numbers with dates since I don't understand very well and immediately their 
    sequence
     
    x1:=Input("point 1 : x1",-100000000,100000000,0);y1:=Input(" 
    y1",-100000000,100000000,0);x2:=Input("point 2 : 
    x2",-100000000,100000000,0);y2:=Input(" 
    y2",-100000000,100000000,0);x3:=Input("Point 3: 
    x3",-100000000,100000000,0);y3:=Input(" 
    y3",-100000000,100000000,0);
     
     
     
    Thanks in advance, Robin
     
     
    <BLOCKQUOTE 
    style="PADDING-RIGHT: 0px; PADDING-LEFT: 5px; MARGIN-LEFT: 5px; BORDER-LEFT: #000000 2px solid; MARGIN-RIGHT: 0px">
      ----- Original Message ----- 
      <DIV 
      style="BACKGROUND: #e4e4e4; FONT: 10pt arial; font-color: black">From: 
      SR 
      To: <A 
      title=Metastockusers@xxxxxxxxxxxxxxx 
      href="mailto:Metastockusers@xxxxxxxxxxxxxxx";>Metastockusers@xxxxxxxxxxxxxxx 
      
      Sent: Saturday, January 04, 2003 2:24 
      PM
      Subject: [Metastockusers] RE:Re: Bar 
      Count since certain date
      bruneski came up with a variation of my approach which 
      is corrects somefailures of my version.So I suggest trying this 
      one:{BarsSinceDate}d:=Input("Day",1,31,1);m:=Input("Month",1,12,1);y:=Input("Year",1920,2030,2002);mydate:= 
      10000*y + 100*m + d;date:= 10000*Year() + 100*Month() + 
      DayOfMonth();count:=BarsSince(mydate<=date); {use '<' if first 
      day is not to becounted}count:=count + 
      Cum(If(count=0,1,0));countTo unsubscribe from 
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