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----- Original Message -----
<DIV
style="BACKGROUND: #e4e4e4; FONT: 10pt arial; font-color: black">From:
Robin Hood
To: <A
title=Metastockusers@xxxxxxxxxxxxxxx
href="mailto:Metastockusers@xxxxxxxxxxxxxxx";>Metastockusers@xxxxxxxxxxxxxxx
Sent: Sunday, January 05, 2003 2:19
PM
Subject: Re: [Metastockusers] RE:Re: Bar
Count since certain date
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style="PADDING-RIGHT: 0px; PADDING-LEFT: 5px; MARGIN-LEFT: 5px; BORDER-LEFT: #000000 2px solid; MARGIN-RIGHT: 0px">
----- Original Message -----
<DIV
style="BACKGROUND: #e4e4e4; FONT: 10pt arial; font-color: black">From:
Robin Hood
To: <A
title=Metastockusers@xxxxxxxxxxxxxxx
href="mailto:Metastockusers@xxxxxxxxxxxxxxx";>Metastockusers@xxxxxxxxxxxxxxx
Sent: Sunday, January 05, 2003 11:50
AM
Subject: Re: [Metastockusers] RE:Re:
Bar Count since certain date
Hi Lionel
Three points are sufficient as parabola is made by tho
"... two
points....."
sorry,
robin
points equidistanced
(whose sum of distances from a
third point fixed is always the same)
<FONT color=#800000
size=5>
<FONT color=#800000
size=5>
robin
<FONT color=#800000
size=5>
(? in english ?) form another one.
<A
href="http://www.xahlee.org/SpecialPlaneCurves_dir/Parabola_dir/parabola.html";>http://www.xahlee.org/SpecialPlaneCurves_dir/Parabola_dir/parabola.html for
examples (by google).
Here is a chart form an Italian site which I don't name because of
netiquette (I think...). They build a parabola from three points, in effect.
It's the same effect I'd like to reproduce with Metastock... but the trouble
are the input dates (x coordinates) :-(
robin
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----- Original Message -----
<DIV
style="BACKGROUND: #e4e4e4; FONT: 10pt arial; font-color: black">From:
Lionel
Issen
To: <A
title=Metastockusers@xxxxxxxxxxxxxxx
href="mailto:Metastockusers@xxxxxxxxxxxxxxx";>Metastockusers@xxxxxxxxxxxxxxx
Sent: Saturday, January 04, 2003 4:57
PM
Subject: RE: [Metastockusers] RE:Re:
Bar Count since certain date
Three points
always define a circle. I think that you need at least 4 points to
define a parabola. When curve fitting a parabola you need more than 4
points as data points always have some noise, they don't fall on a nice
smooth curve.
<FONT
face=Tahoma size=2>-----Original Message-----From: Robin Hood
[mailto:robinhood@xxxxxxxx] Sent: Saturday, January 04, 2003
8:25 AMTo: Metastockusers@xxxxxxxxxxxxxxxSubject:
Re: [Metastockusers] RE:Re: Bar Count since certain
date
Hi Group
Thanks to Spyros for his formula.
In order to build a parabolic trend-line, I need three points
(geometry requires it). It means three x,y (date,
price) coordinates.
The problem is that metastock accepts only six inputs (in oder to
define dates I need 3+3+3=9 inputs :-( ).
Is there another way to make this?
Now, the formula inputs are as follows, but I'd like to
change the numbers with dates since I don't understand very well and
immediately their sequence
x1:=Input("point 1 : x1",-100000000,100000000,0);y1:=Input("
y1",-100000000,100000000,0);x2:=Input("point 2 :
x2",-100000000,100000000,0);y2:=Input("
y2",-100000000,100000000,0);x3:=Input("Point 3:
x3",-100000000,100000000,0);y3:=Input("
y3",-100000000,100000000,0);
Thanks in advance, Robin
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----- Original Message -----
<DIV
style="BACKGROUND: #e4e4e4; FONT: 10pt arial; font-color: black">From:
SR
To: <A
title=Metastockusers@xxxxxxxxxxxxxxx
href="mailto:Metastockusers@xxxxxxxxxxxxxxx";>Metastockusers@xxxxxxxxxxxxxxx
Sent: Saturday, January 04, 2003
2:24 PM
Subject: [Metastockusers] RE:Re:
Bar Count since certain date
bruneski came up with a variation of my approach
which is corrects somefailures of my version.So I suggest trying
this
one:{BarsSinceDate}d:=Input("Day",1,31,1);m:=Input("Month",1,12,1);y:=Input("Year",1920,2030,2002);mydate:=
10000*y + 100*m + d;date:= 10000*Year() + 100*Month() +
DayOfMonth();count:=BarsSince(mydate<=date); {use '<' if first
day is not to becounted}count:=count +
Cum(If(count=0,1,0));countTo unsubscribe
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