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----- Original Message -----
<DIV
style="BACKGROUND: #e4e4e4; FONT: 10pt arial; font-color: black">From:
Robin Hood
To: <A
title=Metastockusers@xxxxxxxxxxxxxxx
href="mailto:Metastockusers@xxxxxxxxxxxxxxx">Metastockusers@xxxxxxxxxxxxxxx
Sent: Sunday, January 05, 2003 11:50
AM
Subject: Re: [Metastockusers] RE:Re: Bar
Count since certain date
Hi Lionel
Three points are sufficient as parabola is made by tho
"... two
points....."
sorry,
robin
points equidistanced (? in english ?) form another one.
<A
href="http://www.xahlee.org/SpecialPlaneCurves_dir/Parabola_dir/parabola.html">http://www.xahlee.org/SpecialPlaneCurves_dir/Parabola_dir/parabola.html for
examples (by google).
Here is a chart form an Italian site which I don't name because of
netiquette (I think...). They build a parabola from three points, in effect.
It's the same effect I'd like to reproduce with Metastock... but the trouble
are the input dates (x coordinates) :-(
robin
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----- Original Message -----
<DIV
style="BACKGROUND: #e4e4e4; FONT: 10pt arial; font-color: black">From:
Lionel
Issen
To: <A
title=Metastockusers@xxxxxxxxxxxxxxx
href="mailto:Metastockusers@xxxxxxxxxxxxxxx">Metastockusers@xxxxxxxxxxxxxxx
Sent: Saturday, January 04, 2003 4:57
PM
Subject: RE: [Metastockusers] RE:Re:
Bar Count since certain date
Three points
always define a circle. I think that you need at least 4 points to
define a parabola. When curve fitting a parabola you need more than 4 points
as data points always have some noise, they don't fall on a nice smooth
curve.
<FONT
face=Tahoma size=2>-----Original Message-----From: Robin Hood
[mailto:robinhood@xxxxxxxx] Sent: Saturday, January 04, 2003 8:25
AMTo: Metastockusers@xxxxxxxxxxxxxxxSubject: Re:
[Metastockusers] RE:Re: Bar Count since certain date
Hi Group
Thanks to Spyros for his formula.
In order to build a parabolic trend-line, I need three points (geometry
requires it). It means three x,y (date, price) coordinates.
The problem is that metastock accepts only six inputs (in oder to
define dates I need 3+3+3=9 inputs :-( ).
Is there another way to make this?
Now, the formula inputs are as follows, but I'd like to change the
numbers with dates since I don't understand very well and immediately their
sequence
x1:=Input("point 1 : x1",-100000000,100000000,0);y1:=Input("
y1",-100000000,100000000,0);x2:=Input("point 2 :
x2",-100000000,100000000,0);y2:=Input("
y2",-100000000,100000000,0);x3:=Input("Point 3:
x3",-100000000,100000000,0);y3:=Input("
y3",-100000000,100000000,0);
Thanks in advance, Robin
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----- Original Message -----
<DIV
style="BACKGROUND: #e4e4e4; FONT: 10pt arial; font-color: black">From:
SR
To: <A
title=Metastockusers@xxxxxxxxxxxxxxx
href="mailto:Metastockusers@xxxxxxxxxxxxxxx">Metastockusers@xxxxxxxxxxxxxxx
Sent: Saturday, January 04, 2003 2:24
PM
Subject: [Metastockusers] RE:Re: Bar
Count since certain date
bruneski came up with a variation of my approach which
is corrects somefailures of my version.So I suggest trying this
one:{BarsSinceDate}d:=Input("Day",1,31,1);m:=Input("Month",1,12,1);y:=Input("Year",1920,2030,2002);mydate:=
10000*y + 100*m + d;date:= 10000*Year() + 100*Month() +
DayOfMonth();count:=BarsSince(mydate<=date); {use '<' if first
day is not to becounted}count:=count +
Cum(If(count=0,1,0));countTo unsubscribe from
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