Re: [Metastockusers] MetaStock ADX vs. RealTick ADX

["David Hunt" <david@xxxxxxxxxxxx>]

 Traders Resources 






 

Roy,
The ADX does not use Exponential MAs in its calculation.
Your point is taken though. 

Warmest Regards
David Hunt________________________________
www.adest.com.au
Phone: Australia:    (02) 9527 4690              Int:            + 61 2  9527 4690
             USA  :        + 1 312 577 0491________________________________
-------Original Message-------
 

From: Metastockusers@xxxxxxxxxxxxxxx
Date: Thursday, November 07, 2002 17:22:31
To: Metastockusers@xxxxxxxxxxxxxxx
Subject: Re: [Metastockusers] MetaStock ADX vs. RealTick ADX
 David> The ADX function in the MetaStock (7 and below)  Explorer function> gives whacky results too,> Warmest Regards> David HuntIf the exploration is set to "Minimum" periods then the results will be wayoff in Metastock. The nature of any exponential MA (EMA, Wilders etc.)requires that a significant "lead-in" time be allowed for the exploredvalues to approximate the chart values. As a rule of thumb one shouldmultiply the longest EMA period by a factor of at least five to determinethe necessary periods setting for the exploration.The simple reason for the apparent problem is that an exponential movingaverage contains a portion of ALL previous data. Therefore it's quitelogical that EMA's with a different length of historical data will givedifferent results. Extending the periods in an MS exploration is one way ofminimising the problem. If a chart is based on 1000 records and anexploration also uses 1000 records then the EMA values will be identical.I'll discuss these and other aspects of EMA and Wilders in a reply to Gary'snote shortly.RoyTo unsubscribe from this group, send an email to:Metastockusers-unsubscribe@xxxxxxxxxxxYour use of Yahoo! Groups is subject to the Yahoo! Terms of Service. 
 

 


















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