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What is your intention with this formula? What are you tringto measure? And what
does it mean or forecast for the future?
Dave Nadeau wrote:
> Try this one out:
>
> Value1:=0.88*Ref(PREV,-6)+Close;
> Value2:=(1.2*Ref(PREV,-6))-(0.7*Ref(PREV,-12));
> ROC(Value1,6,$)+Value2
>
> --------------------------------------
> I can get away with the last statement because
> ROC(Value1,6,$)=Value1-Ref(Value1,-6)
>
> The above plots on Metastock Pro 7.03.
>
> Dave Nadeau
> Fort Collins, CO
>
> 3/5/2001 3:19:56 PM, "Brooke" <brookelise@xxxxxxxx> wrote:
>
> >Corey:
> >
> >I don't think that'll do the job, because the formulas are self-referential,
> >or recursive. Did you get values with it? If so, you're working with a later
> >version of Metastock than I am.
> >
> >I would have thought that you'd need to use PREV. I don't get anything with
> >this in Metastock, for example:
> >
> >Value1:=Ref(Value1,-1) + C;
> >Value1;
> >
> >What that formula would be trying to say is:
> >
> >Value1:=PREV +C;
> >Value1;
> >
> >The first line in the formula would be this, I think:
> >
> >Value1:=0.088*ref(PREV,-6) +C;
> >
> >But the Easy Language formula requires two PREV's in this line:
> >
> >Value2 = Value1 - Value1[6] + 1.2*Value2[6] - 0.7*Value2[12];
> >
> >It might be translated as:
> >
> >Value2:= 1.2*ref(PREV,-6) - 0.7*ref(PREV,-12) + Value1 - ref(Value1,-6) ;
> >
> >Except that
> >
> >a) PREV now refers back to the other PREV in the line, I think, and
> >
> >b) I get an "Add Overflow" message with that formula.
> >
> >So it would have to be broken down in some way so that there was only one
> >PREV in the line.
> >
> >Something like this, though this still won't do it. I'd have to have an
> >EasyLanguage program to compare values.
> >
> >Value1:=0.088*ref(PREV,-6) +C;
> >Value2a:= 1.2*ref(PREV,-6)+ (Value1 - ref(Value1,-6)) ;
> >Value2b:= 0.7*ref(PREV,-12)+(Value1 - ref(Value1,-6)) ;
> >Value2:=Value2a +Value2b;
> >
> >But who knows? Maybe I'm wrong, and newer versions of Metastock can do
> >recursive formulas without PREV.
> >
> >----- Original Message -----
> >From: "C.S." <csaxe@xxxxxxxxxxx>
> >To: <metastock@xxxxxxxxxxxxx>
> >Sent: Monday, March 05, 2001 4:55 PM
> >Subject: Re: EasyLanguage to Metastock conversion
> >
> >
> >> OK,
> >> I'll take a stab at this. Please chime in if I'm wrong, as I can learn
> >> from this too.
> >>
> >> Value1:=C + 0.088 * Ref(Value1,-6);
> >> Value2:=Value1 - Ref(Value1,-6) + 1.2*Ref(Value2,-6) -
> >0.7*Ref(Value2,-12);
> >> Ref(Value2,-12) - 2*Ref(Value2,-6) + Value2
> >>
> >> Although the PREV function could have been used, I didn't because it tends
> >> to slow computation.
> >> -Corey
> >>
> >> ----- Original Message -----
> >> From: "Jeff Haferman" <haferman@xxxxxxxxxxxxxxxxxxxxxxx>
> >> To: <metastock@xxxxxxxxxxxxx>
> >> Sent: Sunday, March 04, 2001 5:03 PM
> >> Subject: EasyLanguage to Metastock conversion
> >>
> >>
> >> >
> >> > I've got some code I'm trying to convert to Metastock...
> >> > it's written in EasyLanguage.
> >> >
> >> > I've got:
> >> >
> >> > Value1 = Close + 0.088*Value1[6];
> >> > Value2 = Value1 - Value1[6] + 1.2*Value2[6] - 0.7*Value2[12];
> >> > D = Value2[12] - 2*Value2[6] + Value2;
> >> > Plot1(D,"D");
> >> >
> >> > Is there an easy way to write this as a Metastock indicator?
> >> > For example, Value1[6] means the value of Value1 6 bars ago.
> >> > But Value1 is defined recursively, so I'm not sure
> >> > how this can be done in Metastock.
> >> >
> >> >
> >> >
> >>
> >>
> >
>
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