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Try this one out:
Value1:=0.88*Ref(PREV,-6)+Close;
Value2:=(1.2*Ref(PREV,-6))-(0.7*Ref(PREV,-12));
ROC(Value1,6,$)+Value2
--------------------------------------
I can get away with the last statement because
ROC(Value1,6,$)=Value1-Ref(Value1,-6)
The above plots on Metastock Pro 7.03.
Dave Nadeau
Fort Collins, CO
3/5/2001 3:19:56 PM, "Brooke" <brookelise@xxxxxxxx> wrote:
>Corey:
>
>I don't think that'll do the job, because the formulas are self-referential,
>or recursive. Did you get values with it? If so, you're working with a later
>version of Metastock than I am.
>
>I would have thought that you'd need to use PREV. I don't get anything with
>this in Metastock, for example:
>
>Value1:=Ref(Value1,-1) + C;
>Value1;
>
>What that formula would be trying to say is:
>
>Value1:=PREV +C;
>Value1;
>
>The first line in the formula would be this, I think:
>
>Value1:=0.088*ref(PREV,-6) +C;
>
>But the Easy Language formula requires two PREV's in this line:
>
>Value2 = Value1 - Value1[6] + 1.2*Value2[6] - 0.7*Value2[12];
>
>It might be translated as:
>
>Value2:= 1.2*ref(PREV,-6) - 0.7*ref(PREV,-12) + Value1 - ref(Value1,-6) ;
>
>Except that
>
>a) PREV now refers back to the other PREV in the line, I think, and
>
>b) I get an "Add Overflow" message with that formula.
>
>So it would have to be broken down in some way so that there was only one
>PREV in the line.
>
>Something like this, though this still won't do it. I'd have to have an
>EasyLanguage program to compare values.
>
>Value1:=0.088*ref(PREV,-6) +C;
>Value2a:= 1.2*ref(PREV,-6)+ (Value1 - ref(Value1,-6)) ;
>Value2b:= 0.7*ref(PREV,-12)+(Value1 - ref(Value1,-6)) ;
>Value2:=Value2a +Value2b;
>
>But who knows? Maybe I'm wrong, and newer versions of Metastock can do
>recursive formulas without PREV.
>
>----- Original Message -----
>From: "C.S." <csaxe@xxxxxxxxxxx>
>To: <metastock@xxxxxxxxxxxxx>
>Sent: Monday, March 05, 2001 4:55 PM
>Subject: Re: EasyLanguage to Metastock conversion
>
>
>> OK,
>> I'll take a stab at this. Please chime in if I'm wrong, as I can learn
>> from this too.
>>
>> Value1:=C + 0.088 * Ref(Value1,-6);
>> Value2:=Value1 - Ref(Value1,-6) + 1.2*Ref(Value2,-6) -
>0.7*Ref(Value2,-12);
>> Ref(Value2,-12) - 2*Ref(Value2,-6) + Value2
>>
>> Although the PREV function could have been used, I didn't because it tends
>> to slow computation.
>> -Corey
>>
>> ----- Original Message -----
>> From: "Jeff Haferman" <haferman@xxxxxxxxxxxxxxxxxxxxxxx>
>> To: <metastock@xxxxxxxxxxxxx>
>> Sent: Sunday, March 04, 2001 5:03 PM
>> Subject: EasyLanguage to Metastock conversion
>>
>>
>> >
>> > I've got some code I'm trying to convert to Metastock...
>> > it's written in EasyLanguage.
>> >
>> > I've got:
>> >
>> > Value1 = Close + 0.088*Value1[6];
>> > Value2 = Value1 - Value1[6] + 1.2*Value2[6] - 0.7*Value2[12];
>> > D = Value2[12] - 2*Value2[6] + Value2;
>> > Plot1(D,"D");
>> >
>> > Is there an easy way to write this as a Metastock indicator?
>> > For example, Value1[6] means the value of Value1 6 bars ago.
>> > But Value1 is defined recursively, so I'm not sure
>> > how this can be done in Metastock.
>> >
>> >
>> >
>>
>>
>
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