Valuewhen returns a array, therefore you
would need to iterate through the values.
|
SYNTAX
|
valuewhen(_expression_,
ARRAY, n = 1)
|
|
RETURNS
|
ARRAY
|
|
FUNCTION
|
Returns
the value of the ARRAY when the _expression_ was true on the n -th most
recent occurrence. Note: this function allows also 0 and negative values for n
- this enables referencing future
|
|
EXAMPLE
|
valuewhen(
cross( close, ma(close,5) ) ,macd(), 1)
|
Thomas
www.PatternExplorer.com
-----Original Message-----
From: amibroker@xxxxxxxxxxxxxxx [mailto:amibroker@xxxxxxxxxxxxxxx] On Behalf Of
lucianomt
Sent: Thursday, June 25, 2009 11:00 PM
To: amibroker@xxxxxxxxxxxxxxx
Subject: [amibroker] Valuewhen issue
t = array with all troughs
p = array with all peaks
tbar = ValueWhen(t, BarIndex(), 1);
pbar = ValueWhen(p, BarIndex(), 1);
if(pbar < tbar)
{
[CODE]
}
I have two arrays marking all the peaks and troughs,
respectively, previously filled with ZigZag. I want to check whether the peak
or trough comes first, so I tried to get the respective bars using Valuewhen
and then checking using IF.
Why am I getting an error 6 message on the IF statement?
I thought ValueWhen returned a specific value not an array...
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