Re: [amibroker] Re: What is wrong?, AmiBroker Email List Archive

What do you mean be gradient of the slope?

On Fri, Sep 19, 2008 at 9:36 PM, Louis P. <rockprog80@xxxxxxxxx> wrote:

Hi,

I need the gradient of the slope, and for each bar. This is where it is difficult...

Thanks,

Louis

2008/9/19 Tony Grimes <Tonez.Email@xxxxxxxxx>

Louis,
If your looking for the slope & difference between HHV of 20 bars & the current close, all you should need is this:
Pds=20;

LastHighBar = HHVBars(High, Pds);
LastHighVal = HHV(High, Pds);

Slope = IIf(LastHighBar,(Close - LastHighVal) / LastHighBar,0);
CloseDiff = Close - Ref(Close, -LastHighBar);

On Fri, Sep 19, 2008 at 4:51 PM, Louis P. <rockprog80@xxxxxxxxx> wrote:

Hi Tony,

Thank you a lot for your response. I'm still very weak with loops. Last time experimented with one, I had to reboot my computer! :) So do you know how such a loop could work? And if I run, let's say 2 minutes bar for one year, wouldn't that be really really long to deal with? I have PIV with 1.5 GHz ram.

I am looking for a line that ends at each bar and that starts from the HHV of 20 bars, and I want to do things with this bar: e.g. compare the closes between current bar and the HHV to the bar and establish the gradient of that linear regression bar for each bar.

Thanks a lot!

Louis

2008/9/19 Tony Grimes <Tonez.Email@xxxxxxxxx>

Hi Louis,
A loop will work, but how slow - it depends (Speed of your computer, number of bars loaded, how many loops your using etc...). Without seeing what your actually looking for (The end result), I think you could do it with one loop, with only one pass through the loop. The speed should be OK.

Good Luck.
Tony

On Fri, Sep 19, 2008 at 2:47 PM, Louis P. <rockprog80@xxxxxxxxx> wrote:

Hi Tony,

Thanks for the tips. Basically, I'd need a loop and use it on each and every bar of the array to determine the LR, right?

That will slow down my computer a lot, don't you think?

Thanks,

Louis

2008/9/16 Tony Grimes <Tonez.Email@xxxxxxxxx>

SelectedValue takes an array ( of numbers) and returns a single number based on the bar that is selected in the chart.
The first formula worked because SelectedValue was giving you a number.

Look at it this way: Array --> SelectedValue ---> Number.
Remove SelectedValue: Array---->Array.
You can draw a line with single numbers, but not arrays.
You can always use a loop.
You might want to read: Understanding how AFL works, in the Amibroker users guide. Until you really understand AFL & array processing, you are going to keep running into these problems, which will just slow you down.

On Tue, Sep 16, 2008 at 10:34 PM, Louis P. <rockprog80@xxxxxxxxx> wrote:

Hi Tony,

Why was the first formula working (the one with selectedvalue) and not the second one? Why simply deleting the "selectedvalue" makes it an array that will not be accept in "linearray"?

Is there any way to draw a line without using lastvalue or selectedvalue? Do I need to use a loop?

Thanks,

Louis

2008/9/16 Tony Grimes <Tonez.Email@xxxxxxxxx>

Louis,
All of the variables you are creating for the LineArray function are arrays themselves. Although LineArray generates an array, it does not accept any arrays as inputs. Additionally, your error message was probably different. It probably went from complaining about argument #4 having the incorrect type (which you corrected) to argument #3 having the incorrect type.

On Tue, Sep 16, 2008 at 9:10 PM, Louis P. <rockprog80@xxxxxxxxx> wrote:

Hi,

Thank you for your help.

@Ara:

If in

barhh1 = HHVBars( High, Periods ) ;
bi1 = BarIndex();
y11 = LinearReg( C, barhh1 ) ;
y01 = LinRegIntercept( C, barhh1 ) ;
sl1 = LineArray( bi1-barhh1+0, y01, bi1, y11, 0, True );

I replace

sl1 = LineArray( bi1-barhh1+0, y01, bi1, y11, 0, True );

by

sl1 = LineArray( bi1-barhh1+0, y01, bi1, LastValue(y11), 0, True );

I still have the same error message. I don't know from where it is coming.. unfortunately!

@gp_sydney:

That was a typo, you are right; I arranged that by adding a 1. But still, the problem remains: the last line does not work.

One day, I asked support if I needed a loop to do such LR and they said I should not need one.

Here is the original code:

barhh = SelectedValue( HHVBars( High, Periods ) );
bi = SelectedValue( BarIndex() );
y1 = SelectedValue( LinearReg( C, barhh ) );
y0 = SelectedValue( LinRegIntercept( C, barhh ) );
sl = LineArray( bi-barhh+0, y0, bi, y1, 0, True );

What I want to do is simply eliminate the "selectedvalue" part and use the code not only for the selected data but for the whole data. I want to be able to draw a line from each HHV to each bar and then work with the result.

If it can't be done without a loop, I feel like I'll be lost in time again; last time I tried to run a loop on my computer it freezed and after 2 minutes I decided to shut down AB...

Thanks for the help,

Louis

2008/9/16 gp_sydney <gp.investment@xxxxxxxxx>

As Ara said, in the shown code snippet you don't have "barhh" defined,
only "barhh1".

Beyond that, you have the same issue I mentioned originally, that the
linear regression functions and LineArray function take scalar values
(ie. single numbers) as parameters, not arrays.

I gather you're trying to create a line from the most-recent HHV value
using the subsequent close data for every bar on the chart. As I don't
think the linear regression functions can take arrays for the period,
I think you'd need to use a loop and do the linear regression yourself
at each bar (you could call the array functions within the loop, but
since they fill a whole array each time, they would do a lot of
unnecessary work). If you do that yourself inside the loop, then at
each bar you'd have scalar 'x' and 'y' values to calculate the line
slope and so on.

For what it's worth, the BarIndex function simply gives you the bar
number. It provides a way of using the current bar number in array
formula.

Regards,
GP

--- In amibroker@xxxxxxxxxxxxxxx, "Louis P." <rockprog80@xxx> wrote:
>
> Hi,
>
> Sorry, You can replace "periods" by 50 if you wish. I just forgot to
> include that.
>
> barhh1 = HHVBars( High, *50* ) ;
> bi1 = BarIndex() ;
> y11 = LinearReg( C, barhh ) ;
> y01 = LinRegIntercept( C, barhh ) ;
> sl1 = LineArray( bi1-barhh1+0, y01, bi1, y11, 0, True );
>
> Still, it is not working, even if barhh1 is defined...
>
> Louis
>
> 2008/9/16 Ara Kaloustian <ara1@xxx>

>
> > y11 and y01 use "barhh" which is not defined.
> >
> > You have defined "barhh1"
> >
> >
> >
> > ----- Original Message -----
> > *From:* Louis P. <rockprog80@xxx>
> > *To:* amibroker@xxxxxxxxxxxxxxx
> > *Sent:* Tuesday, September 16, 2008 2:46 PM
> > *Subject:* [amibroker] What is wrong?
> >
> > Hi,
> >
> > What is wrong in the following formula?
> >
> > barhh1 = HHVBars( High, Periods ) ;
> > bi1 = BarIndex() ;
> > y11 = LinearReg( C, barhh ) ;
> > y01 = LinRegIntercept( C, barhh ) ;
> > sl1 = LineArray( bi1-barhh1+0, y01, bi1, y11, 0, True );
> >
> >
> > Thanks,
> >
> > Louis
> >
> > p.s. There was "Selectedvalue" in the first four lines but I don't
want to
> > plot it on the chart based on where I am on that chart, but simply
set the
> > variable so I can use the stuff later.
> >
> >
> >
>