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Quick question - is there a compact way to write the following:
Close > At least 4 of the previous 5 Closes
I know I can write out each case like:
Case_1 = C > ref(C,-1) and C > ref(C,-2)and C > ref(C,-3)and C > ref(C,-4)and C > ref(C,-5)
Case_2 = C < ref(C,-1) and C > ref(C,-2)and C > ref(C,-3)and C > ref(C,-4)and C > ref(C,-5)
etc....
and then write if Case _1 or Case _2 or Case_3 or ...
But I'm guessing there must be a simpler way to do this?
Any feedback appreciated.
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