[amibroker] Re: Question on how to use HHV or LLV in a looping function?

["Mike" <sfclimbers@xxxxxxxxx>]

Hi,

I haven't tested any of this for accuracy. But, you can play with the 
following approaches, all of which I've tried to keep within the 
structure of your original code snippet (i.e. assuming that looping 
is necessary).

However, as suggested, looping may not be necessary, and likely is 
not necessary.

If I read HHV correctly, then it will include the current bar in the 
calculation. I'm assuming that you do not want to include the current 
bar when looking at "the last 2 bars", and so have used Ref(..., -1) 
to exclude the current bar. Double check this.

Note too that bar indexing is zero based, so your counter (e.g. i = ) 
needs to be 1 less than you might otherwise expect.

Option 1:

HighestOfTwo = Ref(HHV(High, 2), -1);

for (i = 2; i < BarCount; i++) {
  xyz = HighestOfTwo[i];
  ...
}

Option 2:

HighestOfTwo = Max(Ref(High, -1), Ref(High, -2));

for (i = 2; i < BarCount; i++) {
  xyz = HighestOfTwo[i];
  ...
}

Option 3:

for (i = 2; i < BarCount; i++) {
  xyz = High[i - 1];
  if (High[i - 2] > xyz) xyz = High[i - 2];
  ...
}

Again, things will go significantly faster if you don't need the 
loops.

Mike

--- In amibroker@xxxxxxxxxxxxxxx, "sidhartha70" <sidhartha70@xxx> 
wrote:
>
> Help if we knew the full context of the problem... it is likely that
> you wouldn't need to use HHV/LLV inside a loop. You can probably 
code
> the use of HHV/LLV outside of the loop. if you need one at all...
> 
> 
> --- In amibroker@xxxxxxxxxxxxxxx, "cottondepot" <bill.ghali@> wrote:
> >
> > Need to use HHV/LLV in a loop: 
> > 
> > for (i = 3; i < BarCount; i++) 
> > {
> > xyz=HHV(High[i],2);
> > ...
> > }
> > 
> > Obviously that didn't work. In the loop, I'm trying to use 
the "High" 
> > of the last 2 bars as the "LimitPrice" on an order.
> > 
> > Any pointers would be greatly appreciated.
> >
>



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