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[amibroker] Re: getting the hex out...



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I do not understand the problem. If you only need 100 variables why 8
characters?

A-P is 16 letters.

There are 16X16=256 2 letter combinations, that's more than you need,
if you want no repeated letters, 16X15=240 still more than you need.

Why use more than 2 letters?

3 letters 16X16X16=4096 combinations, 16X15X14=3360 no repeats.

8 characters is has combinations in the trillions.

Overkill?

Bill

--- In amibroker@xxxxxxxxxxxxxxx, Dennis Brown <see3d@xxx> wrote:
>
> Hello,
> 
> I have a problem where I need to make my static variable names unique  
> by appending a unique key string to them.  The key is generated from  
> the string representing a file path.  I found an algorithm that  
> generates a unique single precision floating point number from the  
> sequence of ASCII characters in the string.  My problem is that I want  
> to generate an 8 character sequence of characters (A-P) that represent  
> the eight 4 bit hex characters that make up a 32 bit floating point  
> number.  Of course if it were an integer, I would just keep dividing  
> by 16 to get the characters out, but a floating point number will only  
> give me 6 characters that way.  It is late, so perhaps it is just  
> brain fade, but if anyone has a clue, I would appreciate the hints.   
> Perhaps 6 characters (23 bits) is "good enough".  I am only keying a  
> hundred or so paths.  Perhaps I should just make the key four 6 bit  
> characters?
> 
> Best regards,
> Dennis
>



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