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In the help for linregintercept is this code for plotting the line
x = Cum(1);
lastx = LastValue( x ); Daysback = 10; aa = LastValue( LinRegIntercept(
Close, Daysback) );
bb = LastValue( LinRegSlope( Close, Daysback ) );
y = Aa + bb * ( x - (Lastx - DaysBack) ); Plot( Close, "Close", colorBlack,
styleCandle );
Plot( IIf( x >= (lastx - Daysback), y, -1e10 ), "LinReg", colorRed );
If you just want the linear reg values plotted, like a moving average just
use
Plot( LinearReg( close, 10 ), "LinReg", colorRed );
--
Cheers
Graham
AB-Write >< Professional AFL Writing Service
Yes, I write AFL code to your requirements
http://www.aflwriting.com
On 18/11/06, Charles J. Dudek <trader@xxxxxxxxxxxxxx> wrote:
>
> OK, so how do I fix it? Do I have to write some code that will
> calculate a least squares regression from scratch? I think that will
> be really hairy to try to figure out. Are there any examples of
> formulas written to do the same thing or something similar? None of
> the linearreg formulas on the AB website helped.
>
> --- In amibroker@xxxxxxxxxxxxxxx, "Fred" <ftonetti@xxx> wrote:
> >
> > From the doc ...
> >
> > SYNTAX LinRegIntercept( ARRAY, periods )
> >
> > RETURNS ARRAY
> >
> > --- In amibroker@xxxxxxxxxxxxxxx, "Charles J. Dudek" <trader@>
> > wrote:
> > >
> > > And how do I fix it. I'm getting a type mismatch error, but I
> > can't
> > > see where I'm trying to put an entire array into one cell.
> > >
> > > aL[i] = LinRegIntercept( C [i] , Longcount[i] );
> > >
> > > Does LinRegIntercept create an array? If so, how do I get around
> > > that? I'm trying to create trendlines at various points throughout
> > > the history that start and end based on other calculations. This
> > is
> > > driving me CRAZY!!!
> > >
> > > Are there any examples of this kind of thing I could refer to? I
> > know
> > > I could use LineArray, but I also need to calculate standard
> > > deviations based on the same periods, so I don't think that will
> > help
> > > me, will it?
> > >
> > > Chuck
> > >
> >
>
>
>
>
>
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