Re: [amibroker] puzzled by procedure

["Ara Kaloustian" <ara1@xxxxxxxxxx>]

foo ==33 is not a correct structure.

 

== is used as an equality test. Not an assignment of value.

----- Original Message -----

From: cstrader232

To: amibroker@xxxxxxxxxxxxxxx

Sent: Tuesday, May 23, 2006 1:16 PM

Subject: [amibroker] puzzled by procedure

Could someone explain to me why these two function don't work the same way? 

 

Thanks in advance!!

 

foo[BarCount-10] = 33;

procedure FA() {return foo ==33;}

procedure FB() {return StrFind(NumToStr(foo), "3");}

 

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